如何在分隔符文本文件中搜索和删除模式答案

【问题标题】：How to search and delete for pattern inside delimiters text file如何在分隔符文本文件中搜索和删除模式
【发布时间】：2011-11-19 05:15:09
【问题描述】：

我有以下文字：

s:50:"index.php?attachment=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)/trackback/?$";s:35:"index.php?pagename=$matches[1]&tb=1";s:71:"(term-conditions-for-employers)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:66:"(term-conditions-for-employers)/(feed|rdf|rss|rss2|atom|jobman)/?$";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:52:"(term-conditions-for-employers)/page/?([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&paged=$matches[2]";s:59:"(term-conditions-for-employers)/comment-page-([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)(/[0-9]+)?/?$";s:47:"index.php?pagename=$matches[1]&page=$matches[2]";s:26:"home/attachment/([^/]+)/?$";s:32:"index.php?attachment=$matches[1]";s:36:"home/attachment/([^/]+)/trackback/?$";s:37:"index.php?attachment=$matches[1]&tb=1";s:63:"home/attachment/([^/]+)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";s:49:"index.php?attachment=$matches[1]&feed=$matches[2]";s:58:"home/attachment/([^/]+)/(feed|rdf|rss|rss2|atom|jobman)/?$";

我想要做的是搜索单词 jobman 并删除找到该单词的整个条目。每个条目的分隔符是分号“;”。我需要从 Mac OS 命令行执行此操作。所以我有 grep、fgrep 和 awk 等工具可用。

【问题讨论】：

标签： macos sed awk grep delimiter

【解决方案1】：

首先，我们需要从该文本中删除什么？

$> grep -o -P "[^;]*jobman[^;]*;" ./text 
s:71:"(term-conditions-for-employers)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";
s:66:"(term-conditions-for-employers)/(feed|rdf|rss|rss2|atom|jobman)/?$";
s:63:"home/attachment/([^/]+)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";
s:58:"home/attachment/([^/]+)/(feed|rdf|rss|rss2|atom|jobman)/?$";

如果正确，那么

$> sed "s/[^;]*jobman[^;]*;//g" ./text 
s:50:"index.php?attachment=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)/trackback/?$";s:35:"index.php?pagename=$matches[1]&tb=1";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:52:"(term-conditions-for-employers)/page/?([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&paged=$matches[2]";s:59:"(term-conditions-for-employers)/comment-page-([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)(/[0-9]+)?/?$";s:47:"index.php?pagename=$matches[1]&page=$matches[2]";s:26:"home/attachment/([^/]+)/?$";s:32:"index.php?attachment=$matches[1]";s:36:"home/attachment/([^/]+)/trackback/?$";s:37:"index.php?attachment=$matches[1]&tb=1";s:49:"index.php?attachment=$matches[1]&feed=$matches[2]";

我们在"s/[^;]*jobman[^;]*;//g" 中实际做的是搜索[^;]*jobman[^;]*; 符号组（不是: 任何时候，jobman，不是: 任何时候和;）。比我们用''代替它。并对所有文本行进行替换。

【讨论】：