第 16 行的语法错误

Question

对我来说，语法似乎写得正确，但我在第 16 行遇到错误......有什么想法吗？

#!/bin/sh

#This is script is meant to be an add on to another one I'm using. Based on the return code output it will mail me the message.

read -p "What is the file name? " variable
rc = $?

ls -al $variable
if [[ $rc != 0 ]]; then
        mail -s "$variable script did not complete" email address -- -f email address \
        << EOF Your script has failed with error code $rc << EOF;
elif [[ $rc = 0 ]]; then
        mail -s "Your script completed" email address -- -f email address \
        << EOF Your script completed with error code $rc. << EOF;
fi

粘贴似乎有点弄乱了格式。这是 pastebin 链接：

http://pastebin.com/1ub1EupC

Answer 1

以<< EOF 开头的here document 需要在它自己的一行的开头结束EOF。

    mail -s "$variable script did not complete" email address -- -f email address << EOF
Your script $variable has failed with error code $rc.
EOF

如果你使用制表符（严格来说是制表符）进行缩进，你可以使用：

    mail -s "$variable script did not complete" email address -- -f email address <<-EOF
    Your script $variable has failed with error code $rc.
    EOF

（我很高兴地假设您的 mail 命令的语法是可以的，尽管我不相信这一点，即使使用 GNU getopt() 重新排序选项。如果两个词 email address 是 email1@us.example.com 和email2@uk.example.com 或类似的东西，那么它会更接近 OK。就我自己而言，我仍然更喜欢选项而不是参数。）

我还希望在电子邮件正文和主题行中包含失败的脚本名称。