批处理文件的 shell 等效代码

Question

我有一个批处理文件要转换成 shell 文件 批处理代码是：

SETLOCAL

SET BASEDIR=C:\hhpps\HomeHealthGrouper
SET HH_CLASSPATH=.;%BASEDIR%\dist\HomeHealthJava.jar;.;%BASEDIR%\dist\HH_PPS_V_API.jar
rem SET JAVA_VERSION=-version:1.7
SET TEST_FILE=%BASEDIR%\TestData\TestDataV7118.txt

rem SET OPTIONS=details=1

java %JAVA_VERSION% -Xms512m -Xmx512m -Djava.util.logging.config.file="%BASEDIR%\config\logging.properties" ^
    -classpath "%HH_CLASSPATH%" com.mmm.cms.homehealth.test.HomeHealthGrouper_HP ^
    "input=%TEST_FILE%" "config=%BASEDIR%\config\HomeHealthGrouper.properties" ^
    %OPTIONS%

rem reset all variables to prevent locking
SET BASEDIR=
SET HH_CLASSPATH=
SET TEST_FILE=
SET OPTIONS=

 ENDLOCAL

对于上面的代码我写了这个shell代码：

#!/bin/bash
export BASEDIR=/home/bitsbridge/Videos/HomeHealthGrouper
#export JAVA_HOME=/media    /bitsbridge/WIN XP/Program Files/Java/jdk1.6.0/bin/java
#export PATH=$PATH:/usr/java/jdk1.6.0/bin
#export JAVA_HOME
 export HH_CLASSPATH=.:$BASEDIR/dist/HomeHealthJava.jar:$BASEDIR/dist/HH_PPS_V_API.jar
#export CLASSPATH=${CLASSPATH}
classpath=""
input=""
config=""
export JAVA_VERSION=`java -version`                 #/usr/lib/jvm/java-7-oracle/
#temp="java -version"
#JAVA_VERSION=`java -version 2>&1 |awk 'NR==1{ gsub(/"/,""); print $3 }'`
export TEST_FILE=$BASEDIR/TestData/TestDataV6117.txt
export OPTIONS=1

  java $JAVA_VERSION -Xms512m -Xmx512m -Djava.util.logging.config.file="/home/bitsbridge/Videos/HomeHealthGrouper/config/logging.properties"\
            classpath="/home/bitsbridge/Videos/HomeHealthGrouper/dist/HomeHealthJava.jar:/home/bitsbridge/Videos/HomeHealthGrouper/dist/HH_PPS_V_API.jar"  com.mmm.cms.homehealth.test.HomeHealthGrouper_HP\
            input="/home/bitsbridge/Videos/HomeHealthGrouper/TestData/TestDataV6117.txt" config="/home/bitsbridge/Videos/HomeHealthGrouper/config/HomeHealthGrouper.properties"\
            $OPTIONS


 export BASEDIR=""
 export HH_CLASSPATH=""
 export TEST_FILE=""
  export OPTIONS=""

 #${CLASSPATH}:.
 #com.mmm.cms.homehealth.test.HomeHealthGrouper_HP

执行上述代码时出现错误：

错误：无法找到或加载主类 classpath=.home.bitsbridge.Videos.HomeHealthGrouper.dist.HomeHealthJava.jar:.home.bitsbridge.Videos.HomeHealthGrouper.dist.HH_PPS_V_API.jar

但是在执行时它无法加载类路径中提到的 jar 文件并且它给出了错误：

Java(TM) SE 运行时环境 (build 1.7.0_80-b15) Java HotSpot(TM) 服务器 VM（内部版本 24.80-b11，混合模式）错误：无法找到或加载 主班 类路径=.home.Desktop.HPPP.HomeHealthGrouper.dist.HomeHealthJava.jar:.home.D esktop.HPPP.HomeHealthGrouper.dist.HH_PPS_V_API.jar

PS：我已经检查了java路径。

这是/etc/environment/的内容：

PATH="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/usr/lib/$
JAVA_HOME="/usr/lib/jvm/java-7-oracle"

请帮忙找出问题。我被困在这里一个多星期了

我已经更新了上面提到的 shell 代码，并且在 shellcheck.net 上检查过代码是无问题的：

 #!/bin/bash
 BASEDIR=/home/Desktop/HPPP/HomeHealthGrouper
 FILE=/home/Desktop/HPPP/HomeHealthGrouper/config/logging.properties

 export HH_CLASSPATH=.:/home/Desktop/HPPP/HomeHealthGrouper/dist/HomeHealthJava.jar:.:$BASEDIR/dist/HH_PPS_V_API.jar
 JAVA_VERSION="$(java -version)"            
 export JAVA_VERSION
 export TEST_FILE=$BASEDIR/TestData/TestDataV6117.txt
 export OPTIONS=1

 java "$JAVA_VERSION" -Xms512m -Xmx512m -Djava.util.logging.config.file="$FILE"\
 -classpath="/home/Desktop/HPPP/HomeHealthGrouper/dist/HomeHealthJava.jar:/home/Desktop/HPPP/HomeHealthGrouper/dist/HH_PPS_V_API.jar" com.mms.cms.homeHealth.test.HomeHealthGrouper_HP\
 "input=/home/Desktop/HPPP/HomeHealthGrouper/TestData/TestDataV6117.txt" "config=/home/Desktop/HPPP/HomeHealthGrouper/config/HomeHealthGrouper.properties"\
 $OPTIONS


 export BASEDIR=""
 export HH_CLASSPATH=""
 export TEST_FILE=""
 export OPTIONS=""

以上代码执行后的输出：

• ./javaaad.sh java版本“1.7.0_80” Java(TM) SE 运行时环境 (build 1.7.0_80-b15) Java HotSpot(TM) 服务器虚拟机（构建 24.80-b11，混合模式） 错误：无法找到或加载主类

出现错误：

错误：无法找到或加载主类

Answer 1

在类路径开关前添加连字符：classpath=... => -classpath=...。

java -h
...
-classpath <class search path of directories and zip/jar files>
              A : separated list of directories, JAR archives,
              and ZIP archives to search for class files.
...

还将java $JAVA_VERSION ... 更改为java ...，因为现在变量$JAVA_VERSION 中有空字符串，导致额外的参数java '' ...。 java -version 不向 stdout 打印任何内容，向 stderr 打印多行版本描述。