如何在python中合并两个字典？

Question

以下是来自类似输入的巨大文件的示例输入。

{
    "V-Su7890": [
        [
            {
                "url": "www.talent.com",
                "tid": "V-Su7890",
                "id": "58ff787ffbad487b2c",
                "company_name": "Talent Ltd"
            }
        ],
        [
            {
                "socials": ["facebook", "linkedin", "twitter"],
                "title": "title of the pag",
                "contact": ["+9563802140"],
                "email": "email_id1"
            },
            {
                "socials": ["facebook", "twitter", "linkedin"],
                "title": "next title of the page",
                "contact": ["+919765983442"],
                "email": "email_id2"
            }
        ]
    ]
}

我必须将当前字典的第二个列表的所有子字典合并到一个没有重复值的字典中，然后将字典作为值存储到键“V-Su7890”中。

想要的输出是：

{
    "V-Su7890": [
        [
            {
                "url": "www.talent.com",
                "tid": "V-Su7890",
                "id": "58ff787ffbad487b2c",
                "company_name": "Talent Ltd"
            }
        ],
        [
            {
                "socials": ["facebook", "linkedin", "twitter"],
                "title": ["title of the pag", "next title of the page"],
                "contact": ["+9563802140", "+919765983442"],
                "email": ["email_id","email_id2"]
            }
        ]
    ]
}

请帮助我理解并解决这个问题。

Answer 1

您可以使用setdefault() 插入值为默认值的键（这里您可以使用空列表），如果新项目不存在，则使用extend 列表。

for k,v in a.items():
    tmp={}
    for i in v[1]:
        for k1,v2 in i.items():
            if isinstance(v2,list):
                tmp.setdefault(k1,[]).extend(i for i in v2 if i not in tmp[k1])
            else:
                tmp.setdefault(k1,[]).append(v2)
    a[k]=[v[0],[tmp]]
print(a)

结果：

{
  'V-Su7890': [
    ...
    [
      {
        'contact': ['+9563802140','+919765983442'],
        'socials': ['facebook','linkedin','twitter'],
        'email': ['email_id1','email_id2'],
        'title': ['title of the pag','next title of the page']
      }
    ]
  ]
}

Answer 2

假设您将完整的 dict 存储在变量 V 中。我们将 socials、title 等的值存储在一个集合中以避免重复值。稍后，我们会将集合转换为列表。这是解决方案：

V = k["V-Su7890"][1]
new_dict = {}

for v in V:
    for key, value in v.iteritems():
        if not new_dict.get(key, None):
            new_dict[key] = set()

        if isinstance(value, list):
            for val in value:
                new_dict[key].add(val)
        else:
            new_dict[key].add(value)

# Converting the sets to list
for key, value in new_dict.iteritems():
    new_dict[key] = list(value)

k["V-Su7890"][1] = [new_dict]