如何从 django shell 中的脚本保存多个对象

Question

你好同事我想知道这个对象列表是否可以从我展示的脚本中保存，我想从 django shell 执行它

python3 manage.py shell < script.py

以下是我的脚本

from orders_management.models import Products


objects = [
    'Products(name = "destornillador", section = "ferrreteria", price = 35)',
    'Products(name = "balon", section = "deportes", price = 25)',
    'Products(name = "raqueta", section = "deportes", price = 105)',
    'Products(name = "muneca", section = "juguetes", price = 15)',
    'Products(name = "tren electrico", section = "jugueteria", price = 135)',
]

for object in objects:
    my_product = object
    my_product.save()

它显示给我的错误

  File "<string>", line 15, in <module>
AttributeError: 'str' object has no attribute 'save'

Answer 1

那是因为您将产品包装在一个字符串中。试试这种方式（不围绕产品引用）：

objects = [
    Products(name = "destornillador", section = "ferrreteria", price = 35),
    Products(name = "balon", section = "deportes", price = 25),
    Products(name = "raqueta", section = "deportes", price = 105),
    Products(name = "muneca", section = "juguetes", price = 15),
    Products(name = "tren electrico", section = "jugueteria", price = 135),
]

for object in objects:
    my_product = object
    my_product.save()

Answer 2

您在单引号之间写了<b>'</b>Products()<b>'</b>，因此作为string，而不是作为Product 对象。

此外，您最好使用.bulk_create(…) [Django-doc] 而不是手动保存每个对象，因为这将在单个查询中完成：

从 orders_management.models 导入产品

objects = [
    # no '…'
    Products(name = "destornillador", section = "ferrreteria", price = 35),
    Products(name = "balon", section = "deportes", price = 25),
    Products(name = "raqueta", section = "deportes", price = 105),
    Products(name = "muneca", section = "juguetes", price = 15),
    Products(name = "tren electrico", section = "jugueteria", price = 135),
]

Products.objects.bulk_create(objects)

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注意：通常 Django 模型被赋予一个单数名称，所以Product而不是Products。