如何合并具有不同行数的两个矩阵答案

【问题标题】：How to merge two matrices with differing number of rows如何合并具有不同行数的两个矩阵
【发布时间】：2012-11-08 10:27:13
【问题描述】：

假设我有 2 个如下所示的矩阵：

structure(c(0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211), .Dim = c(14L, 
1L), .Dimnames = list(c("ch5_98500001", "ch5_99500001", "ch5_100500001", 
"ch5_101500001", "ch5_102500001", "ch5_103500001", "ch5_104500001", 
"ch5_105500001", "ch5_106500001", "ch5_110500001", "ch5_111500001", 
"ch5_112500001", "ch5_113500001", "ch5_114500001"), "loh"))
                    loh
ch5_98500001  0.3157895
ch5_99500001  0.3157895
ch5_100500001 0.3157895
ch5_101500001 0.3157895
ch5_102500001 0.3157895
ch5_103500001 0.3157895

structure(c(0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.315789473684211, 0.315789473684211, 
0.315789473684211, 0.315789473684211, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579, 
0.368421052631579, 0.368421052631579, 0.368421052631579, 0.368421052631579
), .Dim = c(83L, 1L), .Dimnames = list(c("ch8_20500001", "ch8_21500001", 
"ch8_22500001", "ch8_23500001", "ch8_24500001", "ch8_25500001", 
"ch8_26500001", "ch8_27500001", "ch8_28500001", "ch18_500001", 
"ch18_1500001", "ch18_2500001", "ch18_3500001", "ch18_4500001", 
"ch18_5500001", "ch18_6500001", "ch18_7500001", "ch18_8500001", 
"ch18_9500001", "ch18_10500001", "ch18_11500001", "ch18_12500001", 
"ch18_13500001", "ch18_14500001", "ch18_15500001", "ch18_16500001", 
"ch18_17500001", "ch18_18500001", "ch18_19500001", "ch18_20500001", 
"ch18_21500001", "ch18_24500001", "ch18_25500001", "ch18_26500001", 
"ch18_27500001", "ch18_28500001", "ch18_29500001", "ch18_30500001", 
"ch18_31500001", "ch18_32500001", "ch18_33500001", "ch18_34500001", 
"ch18_35500001", "ch18_36500001", "ch18_37500001", "ch18_38500001", 
"ch18_39500001", "ch18_40500001", "ch18_41500001", "ch18_42500001", 
"ch18_43500001", "ch18_44500001", "ch18_45500001", "ch18_46500001", 
"ch18_47500001", "ch18_48500001", "ch18_49500001", "ch18_50500001", 
"ch18_51500001", "ch18_52500001", "ch18_53500001", "ch18_54500001", 
"ch18_55500001", "ch18_56500001", "ch18_57500001", "ch18_58500001", 
"ch18_59500001", "ch18_60500001", "ch18_61500001", "ch18_62500001", 
"ch18_63500001", "ch18_64500001", "ch18_65500001", "ch18_66500001", 
"ch18_67500001", "ch18_68500001", "ch18_69500001", "ch18_70500001", 
"ch18_71500001", "ch18_72500001", "ch18_73500001", "ch18_74500001", 
"ch18_75500001"), "loss"))
                  loss
ch8_20500001 0.3157895
ch8_21500001 0.3157895
ch8_22500001 0.3157895
ch8_23500001 0.3157895
ch8_24500001 0.3157895
ch8_25500001 0.3157895
ch8_26500001 0.3157895
ch8_27500001 0.3157895
ch8_28500001 0.3157895
ch18_500001  0.3157895
ch18_1500001 0.3157895
ch18_2500001 0.3157895

我希望它们合并到 1 个 data.frame 或矩阵中，以便我有一个概览并且不需要在文件之间切换。但是解决这个问题似乎比只使用data.frame更难。

有人知道如何不解决行长不同的问题吗？

【问题讨论】：

@jem77bfp 3 帧或更多帧也可以吗？
@jem77bfp 谢谢！列表完美无缺

标签： r matrix dataframe

【解决方案1】：

 merge(as.data.frame(loss), as.data.frame(loh), by="row.names")

但它给出了空数据框，因为您的两个矩阵中都没有匹配的行名。你也可以这样做

 merge(as.data.frame(loss), as.data.frame(loh), by="row.names", all=TRUE)

对于多个数据框，我会使用函数Reduce。

 Reduce(merge, list(data1, ..., dataN)))

确保您也将by 参数传递给merge。

【讨论】：