选择两列中记录的最大总和

Question

我需要选择联盟中得分最高的球队。这是比赛栏，它确实取决于 m_id 如果你是 team1_id 或 team2_id 与分数相同，因为联赛中也有复赛。

 CREATE TABLE IF NOT EXISTS `xeg8u_bl_match` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `m_id` int(11) NOT NULL DEFAULT '0',
  `team1_id` int(11) NOT NULL DEFAULT '0',
  `team2_id` int(11) NOT NULL DEFAULT '0',
  `score1` int(11) NOT NULL DEFAULT '0',
  `score2` int(11) NOT NULL DEFAULT '0',
  `match_descr` text NOT NULL,
  `published` char(1) NOT NULL DEFAULT '0',
  `is_extra` char(1) NOT NULL DEFAULT '0',
  `m_played` char(1) NOT NULL DEFAULT '0',
  `m_date` date NOT NULL DEFAULT '0000-00-00',
  `m_time` varchar(10) NOT NULL DEFAULT '',
  `m_location` varchar(255) NOT NULL,
  `bonus1` decimal(10,2) NOT NULL DEFAULT '0.00',
  `bonus2` decimal(10,2) NOT NULL DEFAULT '0.00',
  `team1_strzaly` varchar(255) NOT NULL,
  `team1_strzalyc` varchar(255) NOT NULL,
  `team1_posiadanie` varchar(255) NOT NULL,
  `team1_przejecia` varchar(255) NOT NULL,
  `team1_faule` varchar(255) NOT NULL,
  `team1_zkartki` varchar(255) NOT NULL,
  `team1_ckartki` varchar(255) NOT NULL,
  `team1_kontuzje` varchar(255) NOT NULL,
  `team1_spalone` varchar(255) NOT NULL,
  `team1_rrozne` varchar(255) NOT NULL,
  `team1_celnosc` varchar(255) NOT NULL,
  `team1_dpodan` varchar(255) NOT NULL,
  `team2_strzaly` varchar(255) NOT NULL,
  `team2_strzalyc` varchar(255) NOT NULL,
  `team2_posiadanie` varchar(255) NOT NULL,
  `team2_przejecia` varchar(255) NOT NULL,
  `team2_faule` varchar(255) NOT NULL,
  `team2_zkartki` varchar(255) NOT NULL,
  `team2_ckartki` varchar(255) NOT NULL,
  `team2_kontuzje` varchar(255) NOT NULL,
  `team2_spalone` varchar(255) NOT NULL,
  `team2_rrozne` varchar(255) NOT NULL,
  `team2_celnosc` varchar(255) NOT NULL,
  `team2_dpodan` varchar(255) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=399 ;

现在我正在考虑在 SELECT、MAX 和 SUM 中使用两个函数，我试图做到这一点，但我不知道如何让它发挥作用，我知道如何显示指定球队的主场和客场进球数但我不知道如何查看哪支球队是最佳射手。有什么想法吗？

好吧，毕竟我决定试一试。所以我解决了它，它确实有效，但我的问题是是否有任何方法可以更轻松地完成它，是否需要以不同的方式完成它？

    //season_id
$link = ConnectToMySql();
$wynik = mysqli_query($link, "SELECT season_id FROM xeg8u_bl_season_teams WHERE team_id = '$teamekid' LIMIT 1");
$m_id = mysqli_fetch_array($wynik);
$r4 = $m_id[0];

//sprawdzam jakie id dni meczowych znajdują się w sezonie o id x
$link = ConnectToMySql();
$wynik = mysqli_query($link, "SELECT MIN(id) FROM xeg8u_bl_matchday WHERE s_id = '$r4'");
$m_id = mysqli_fetch_array($wynik);
$min_r1 = $m_id[0];

$link = ConnectToMySql();
$wynik = mysqli_query($link, "SELECT MAX(id) FROM xeg8u_bl_matchday WHERE s_id = '$r4'");
$m_id = mysqli_fetch_array($wynik);
$max_r1 = $m_id[0];

$link = ConnectToMySql();
$wynik = mysqli_query($link, "SELECT m_id FROM xeg8u_bl_match WHERE m_id LIKE '$r1'");
$id = mysqli_fetch_array($wynik);
$r2 = $id[0];



$link = ConnectToMySql();
$wynik = mysqli_query($link, "Select team, sum(score) as totalscore from (select team1_id as team, sum(score1) as score from xeg8u_bl_match WHERE m_id BETWEEN '$min_r1' AND '$max_r1' group by team1_id union all select team2_id as team, sum(score2) as score from xeg8u_bl_match WHERE m_id BETWEEN '$min_r1' AND '$max_r1' group by team2_id) as scores group by team order by totalscore asc limit 1");
$krol = mysqli_fetch_array($wynik);
$r3 = $krol[0];

这样就可以了，还是有更简单、更好看的方法？ 正如我所说，它现在确实有效:) 谢谢你们。

Answer 1

我想你需要这个：

select team, sum(score) as totalscore
from
(
    select team1_id as team, sum(score1) as score
    from xeg8u_bl_match
    group by team1_id
    union all
    select team2_id as team, sum(score2) as score
    from xeg8u_bl_match
    group by team2_id
) as scores
group by team
order by 2 desc
limit 1