SQL 如果匹配则更新如果不匹配则插入答案

【问题标题】：SQL if matched update if not matched then insertSQL 如果匹配则更新如果不匹配则插入
【发布时间】：2014-01-26 18:45:06
【问题描述】：

请帮忙解决这个问题... 我正在尝试在 VB 中实现此 SQL 代码，代码适用于更新但不适用于插入...

merge into anamneza a
using (select ana_id from anamneza where ana_id = 2) e 
on (a.ana_id = e.ana_id)
when matched then 
update set a.ana_kupanje = 'da' 
when not matched then
insert (ana_rb,ana_id,ana_kupanje,ana_kosa,ana_brijanje,ana_zubi,ana_nokti,ana_odjeca,ana_koza,ana_dek_rizik,ana_dek_rizik_gdje,ana_dek_postojeci,ana_dek_post_gdje,ana_pokretnost,ana_kolica,ana_pomagala,azurirao,datumazur)
values (1,1,'da','da','da','da','da','da','da','da','da','da','da','da','da','da','veki',getdate());

首先我在 SQLQuery 中编写并执行它，它说（0 行受影响）

但是当我插入该行并且它的 id=1 并更改选择它匹配 ana_id = 1 时，它说（1 行受影响）；

为什么插入语句不起作用？？？

【问题讨论】：

Please reconsider using MERGE for this at all.
是否返回错误？
没有错误，只有 0 行受到影响，当我在执行时手动插入时，它会更新字段...奇怪
如果来自 Aaron B 的链接消失；合并有错误，一些被标记为不会修复。
我想这已经被问过了：stackoverflow.com/questions/10794870/…

标签： sql sql-server vb.net sql-server-2008

【解决方案1】：

按照Using SQL Server MERGE command with same source & target table 中的建议，将MERGE 语句的第2 行替换为：

using (
    select 1 as ana_rb, 1 as ana_id,
           'da' as ana_kupanje, 'da' as ana_kosa, 'da' as ana_brijanje,
           'da' as ana_zubi, 'da' as ana_nokti, 'da' as ana_odjeca,
           'da' as ana_koza, 'da' as ana_dek_rizik, 'da' as ana_dek_rizik_gdje,
           'da' as ana_dek_postojeci, 'da' as ana_dek_post_gdje,
           'da' as ana_pokretnost, 'da' as ana_kolica, 'da' as ana_pomagala,
           'veki' as azurirao, getdate() as datumazur
) e

注意：确保值与INSERT 部分中的值匹配！

【讨论】：