【发布时间】:2019-09-23 06:41:55
【问题描述】:
我有两个哈希映射的哈希映射。对于一个实例让,
Hashmap map1 =
key : mapview Value : {backgroundimage=character varying, mapviewname=character varying, mapviewid=character}
key : am_mypage_template_mgs Value : {resourceid=integer, pageid=integer}
key : am_tomcatinfo Value : {resourceid=bigint, url=character varying, sslenabled=character varying}
并且
Hashmap map2 =
key : mapview Value : {backgroundimage=character varying, mapviewname=character varying, mapviewid=integer}
key : am_mypage_template_mgs Value : {resourceid=integer}
我必须比较这两个并找出 map2 中缺少 map1 中的哪些键。如果存在键,我必须比较内部映射并将 map1 的内部映射的键与 map2 的内部映射进行比较。如果存在键,我必须将对应于 map1 的内部映射的值与 map2 进行比较。
我的代码是,
map1.entrySet().forEach(entry -> {
if (map2.containsKey(entry.getKey())) {
if (entry.getValue().equals(map2.get(entry.getKey()))) {
count++;
} else {
entry.getValue().entrySet().forEach(inside_entry->{
if(map2.get(entry.getKey()).containsKey(inside_entry.getKey())) {
Map<String, String> n = new HashMap<String, String>();
n.putAll(map2.get(entry.getKey()));
if((inside_entry.getValue()).equals(map2.get(n))){
}
else {
System.out.println("Tablename1 : "+ entry.getKey() +" Key :"+inside_entry.getKey()+" value : "+inside_entry.getValue());
}
}
});
System.out.println(entry.getValue());
}
} else {
System.out.println("\"" + entry.getKey() + "\" entire table is not found");
}
});
我的输出应该是这样的,
key am_tomcatinfo in map1 missing in map2
In am_mypage_template_mgs, pageid in map1 is missing in map2
In mapview, mapviewid=character in map1 is not equal to mapviewid=integer in map2
我该怎么办?
【问题讨论】: