如何使用 SQL 合并或连接具有相同数据的数据答案

【问题标题】：How to merge or join data which have the same data with SQL如何使用 SQL 合并或连接具有相同数据的数据
【发布时间】：2014-07-16 05:18:56
【问题描述】：

如何将具有相同信息的数据合并或连接到一行，如下图。

SQL：

SELECT C.[LocationCode]
    ,C.[PartNumber]
    ,C.[WorksOrderNumber]
    ,CONVERT(DECIMAL(18,0), C.[BatchQuantity]) AS 'MAC_Outstanding'
FROM CUSTOMER_MN C
WHERE C.[LocationCode] = 'P1'

SELECT R.[LocationCode]
    ,R.[PartNumber]
    ,R.[WorksOrderNumber]
    ,CONVERT(DECIMAL(18,0), R.[PlannedQuantity] - R.[ActualQuantity]) AS 'ASY_Outstanding'
FROM CUSTOMER_RH R
WHERE R.[LocationCode] = 'P1'

【问题讨论】：

标签： sql sql-server merge

【解决方案1】：

为什么不使用join？

SELECT C.[LocationCode]
    ,C.[PartNumber]
    ,C.[WorksOrderNumber]
    ,CONVERT(DECIMAL(18,0), C.[BatchQuantity]) AS 'MAC_Outstanding'
    ,CONVERT(DECIMAL(18,0), R.[PlannedQuantity] - R.[ActualQuantity]) AS 'ASY_Outstanding'
FROM CUSTOMER_MN C
JOIN CUSTOMER_RH R ON C.LocationCode = R.LocationCode AND C.Partnumber = R.Partnumber AND C.WorksOrderNumber = R.WorksOrderNumber
WHERE C.[LocationCode] = 'P1'

【讨论】：

【解决方案2】：

为了合并数据使用UNION ALL:

SELECT C.[LocationCode]
    ,C.[PartNumber]
    ,C.[WorksOrderNumber]
    ,CONVERT(DECIMAL(18,0), C.[BatchQuantity]) AS 'MAC_Outstanding'
FROM CUSTOMER_MN C
WHERE C.[LocationCode] = 'P1'

UNION ALL

SELECT R.[LocationCode]
    ,R.[PartNumber]
    ,R.[WorksOrderNumber]
    ,CONVERT(DECIMAL(18,0), R.[PlannedQuantity] - R.[ActualQuantity]) AS 'ASY_Outstanding'
FROM CUSTOMER_RH R
WHERE R.[LocationCode] = 'P1'

为了合并数据，请使用以下查询：

Select * 
From (
    SELECT C.[LocationCode]
        ,C.[PartNumber]
        ,C.[WorksOrderNumber]
        ,CONVERT(DECIMAL(18,0), C.[BatchQuantity]) AS 'MAC_Outstanding'
    FROM CUSTOMER_MN C
    WHERE C.[LocationCode] = 'P1')z1

Left Join (
    SELECT R.[LocationCode]
        ,R.[PartNumber]
        ,R.[WorksOrderNumber]
        ,CONVERT(DECIMAL(18,0), R.[PlannedQuantity] - R.[ActualQuantity]) AS 'ASY_Outstanding'
    FROM CUSTOMER_RH R
    WHERE R.[LocationCode] = 'P1'
    )z2 On Z1.LocationCode = Z2.LocationCode, Z1.PartNumber = Z2.PartNumber and Z1.WorkOrderNumber = z2.WorkOrderNumber

【讨论】：