不带逗号的字符串到字典解析

Question

有一个奇怪的字符串表示，比如

“key1:value1:key2:value2:key3:value3...keyn:valuen”

我需要创建一个字典，当你有逗号时它很容易解决，但是这里只有冒号，你必须每隔一个冒号拆分一次字符串。带有循环或类似的代码看起来很丑，所以我想知道你是否可以帮助我使用oneliner。

Answer 1

你可以只用冒号分割，get an iterator 分割标记，zip 迭代器本身。这将很好地配对键和值：

s = 'key1:value1:key2:value2:key3:value3:keyn:valuen'
it = iter(s.split(':'))
dict(zip(it, it))
# {'key1': 'value1', 'key2': 'value2', 'key3': 'value3', 'keyn': 'valuen'}

Answer 2

如果您对 iter（以及我认为更好的 schwobaseggls 解决方案）感到不舒服，您可以以几乎相同的方式使用压缩列表切片：

s = 'key1:value1:key2:value2:key3:value3:keyn:valuen'
splitted = s.split(':')

# even_elements = splitted[::2]   - take every 2nd starting at 0th index
# odd_elements  = splitted[1::2]  - take every 2nd startIng at 1st index
k = {k:v for k,v in zip(splitted[::2],splitted [1::2]) }
print(k) 

输出：

{'key1': 'value1', 'key2': 'value2', 'key3': 'value3', 'keyn': 'valuen'}

---

或者，您可以手动创建字典：

s = 'key1:value1:key2:value2:key3:value3:keyn:valuen'
splitted = s.split(':')
d ={}

# this generates 2-slices from the list and puts them into your dict
for k,v in (splitted[i:i+2] for i in range(0,len(splitted),2)):
    d[k] = v

# or d = { k:v for k, v in (splitted[i:i+2] for i in range(0,len(splitted),2) )}
# or d = dict(splitted[i:i+2] for i in range(0,len(splitted),2) )

print(d)

输出：

{'key1': 'value1', 'key2': 'value2', 'key3': 'value3', 'keyn': 'valuen'}