如何使相同的代码适用于多个字典？

Question

我是 python 新手，我做了一个测验，询问用户他们是否想玩简单、中等或困难的游戏，然后代码会根据用户选择的难度显示问题。我有字典中的所有问题和答案（每个难度都有一本字典，例如用于简单问题和答案的字典和用于困难问题和答案的字典等），并且我有这部分代码来检查用户的答案是否正确或错误。问题是检查答案是否正确的代码部分一次只能使用一个字典。另一个问题是我不知道如何使它，如果用户选择简单，那么代码会从简单的字典中打印出简单的问题。if answer.lower() == Question_list_easy[ques]: 部分只允许 1 个字典，这就是为什么我认为代码只有一次允许一个字典。我试过if chooses == "easy": print (Question_list_easy)，但它不起作用。请帮帮我。

import random

quiz_difficulty = input("Would you like to play on easy, medium, or hard\n").lower()
if quiz_difficulty == "easy":
  print (Question_list_easy)
   
if quiz_difficulty == "medium":
   print (Question_list_medium)

if quiz_difficulty == "hard":
   print (Question_list_hard)


Question_list_easy = {
   "How many days are there in a year?":"365",
   "How many hours are there in a day?":"24", 
   "How many days are there in a week?":"7"
   } 

Question_list_medium = {
   "How many weeks are there in a year?":"52",
   "How many years are there in a decade?":"10", 
   "How many days are there in a fortnight?":"14"
   } 

Question_list_hard = {
   "How many years are there in a millennium?":"1000",
   "How many days are there in 2 years?":"730", 
   "How many years are there in a half a century?":"50"
   } 
  


#The part which asks the questions and verifies if the answer the user does is coreect or incorrect. It also randomizes the questions
question = list (Question_list_easy.keys())
#input answer here 
while True:
    if not question:
        break
    ques = random.choice(question)
    print(ques)
    while True:
        answer = input('Answer ' )
        # if correct, moves onto next question
        if answer.lower() == Question_list_easy[ques]:
            print("Correct Answer")
            break
        else:
            #if wrong, Asks the same question again
            print("Wrong Answer, try again")
    question.remove(ques)

Answer 1

尽管有些问题的答案是错误的，但这里有一种方法可以用更少的代码实现您的目标。这里的关键特征是使用字典，其中键/值对是映射到适当问题字典的难度级别。这消除了在选择难度级别时对 if/then/else 的需求，因此如果您想添加更多难度级别，则更具可扩展性：-

Question_list_easy = {
    "How many days are there in a year?": "365",
    "How many hours are there in a day?": "24",
    "How many days are there in a week?": "7"
}

Question_list_medium = {
    "How many weeks are there in a year?": "52",
    "How many years are there in a decade?": "10",
    "How many days are there in a fortnight?": "14"
}

Question_list_hard = {
    "How many years are there in a millennium?": "365",
    "How many days are there in 2 years?": "730",
    "How many days are there in a half a century?": "50"
}

qmap = {'easy': Question_list_easy,
        'medium': Question_list_medium,
        'hard': Question_list_hard}

questions = None

while questions is None:
    inp = input('Would you like to play easy, medium, or hard? ')
    questions = qmap.get(inp)

while len(questions) > 0:
    _i = random.randint(0, len(questions) - 1)
    _key = list(questions)[_i]
    inp = input(_key+' ')
    if inp == questions[_key]:
        print('Correct')
        questions.pop(_key)
    else:
        print('Incorrect. Try again')

Answer 2

这看起来很接近，但我认为你缺少的部分是你可以说：

if quiz_difficulty == "easy":
   question_list = Question_list_easy
if quiz_difficulty == "medium":
   question_list = Question_list_medium
if quiz_difficulty == "hard":
   question_list = Question_list_hard

然后，在您提出问题的部分中，您只需使用 question_list 而不是专门引用 Question_list_easy。

Answer 3

将提出问题的部分放入函数中，并将适当的dict传递给函数，如下所示：

def ask_the_questions(q_dict):
    #The part which asks the questions ons
    question = list (q_dict.keys())
    ... etc ...

然后用合适的dict调用函数，例如：

ask_the_question(Question_list_easy)

Answer 4

我已将您的代码更改如下：

question = ''
question_set = ''
if quiz_difficulty == "easy":
  question = list (Question_list_easy.keys())
  question_set = Question_list_easy
   
if quiz_difficulty == "medium":
   question = list (Question_list_medium.keys())
   question_set = Question_list_medium

if quiz_difficulty == "hard":
   question = list (Question_list_hard.keys())
   question_set = Question_list_hard

while True:
    if not question or not question_set:
        break
    ques = random.choice(question)
    print(ques)
    while True:
        answer = input('Answer ' )
        # if correct, moves onto next question
        if answer.lower() == question_set[ques]:
            print("Correct Answer")
            break
        else:
            #if wrong, Asks the same question again
            print("Wrong Answer, try again")
    question.remove(ques)