如果其他值具有特定属性，则遍历字典列表以获得特定值

Question

我“解码”了一本字典并归结为：

waycategory_values = data['features'][0]['properties']['extras']['waycategory']['summary']

导致：

[{'value': 3.0, 'distance': 230472.2, 'amount': 96.03}, {'value': 0.0, 'distance': 8713.7, 'amount': 3.63}, {'value': 1.0, 'distance': 811.1, 'amount': 0.34}]

现在我想获取距离并将相应的值相加，如果值 = 1.0、2.0 或 3.0 我尝试通过执行以下操作来获取距离：

for distance in waycategory_values[0:]['distance']:
    if waycategory_values[0:]['value'] == 1.0 or 2.0 or 3.0:
        print(distance)

嗯 - 这显然是错误的.. 但似乎无法弄清楚如何去做 - 如果你能给我一个提示，那就太棒了！

Answer 1

data = [{'value': 3.0, 'distance': 230472.2, 'amount': 96.03}, {'value': 0.0, 'distance': 8713.7, 'amount': 3.63}, {'value': 1.0, 'distance': 811.1, 'amount': 0.34}]

total_distance = 0
# just go through the list, no need for indexing
for dataset in data:
    if dataset['value'] in [1.0, 2.0, 3.0]: # <- list of values to check against
        total_distance += dataset['distance']

Answer 2

d=[{'value': 3.0, 'distance': 230472.2, 'amount': 96.03}, {'value': 0.0, 'distance': 8713.7, 'amount': 3.63}, {'value': 1.0, 'distance': 811.1, 'amount': 0.34}]
sum(v['distance'] for v in d if v['value'] == 1 or v['value'] == 2 or   v['value'] ==  3  )

231283.30000000002