【发布时间】:2013-12-01 18:52:15
【问题描述】:
您好,我编写了一个类的两个版本,一个使用地图,一个使用两个向量:
class NucleotideSequence{
private:
std::string Name;
std::vector<int> BasePos;
std::vector<char> BaseChar;
public:
NucleotideSequence(std::string name, std::vector<int> &bp, std::vector<char> &bases);
std::string getName();
char getBase(int pos); // get a base by it's position in the char array.
char getAbBase(int abPos); // get a base by it's actual bp position.
};
class NucleotideSequence2{
private:
std::string Name;
std::map<int, char> Sequence;
public:
NucleotideSequence2(std::string &name, std::map<int, char> &seq) throw(FormatError);
std::string getName();
};
然后我为它们定义了构造函数:
NucleotideSequence::NucleotideSequence(std::string name, std::vector<int> &bp, std::vector<char> &bases)
:Name(name), BasePos(bp), BaseChar(bases)
{
for (std::vector<char>::iterator i = BaseChar.begin(); i != BaseChar.end(); i++) {
switch (*i) {
case 'A': case 'T': case 'C': case 'G': case '-': case 'N':
break;
case 'a':
*i = 'A';
break;
case 't':
*i = 'T';
break;
case 'c':
*i = 'C';
break;
case 'g':
*i = 'G';
break;
case 'n':
*i = 'N';
break;
default:
throw FormatError();
break;
}
}
}
NucleotideSequence2::NucleotideSequence2(std::string &name, std::map<int, char> &seq) throw(FormatError)
: Name(name), Sequence(seq)
{
for (std::map<int, char>::iterator i = Sequence.begin(); i != Sequence.end(); i++) {
switch (i->second) {
case 'A': case 'T': case 'C': case 'G': case '-': case 'N':
break;
case 'a':
i->second = 'A';
break;
case 't':
i->second = 'T';
break;
case 'c':
i->second = 'C';
break;
case 'g':
i->second = 'G';
break;
case 'n':
i->second = 'N';
break;
default:
throw FormatError();
break;
}
}
}
这两个构造函数在两个不同的函数中调用:
NucleotideSequence Sequence_stream::get()
{
if (FileStream.is_open() == false)
throw StreamClosed(); // Make sure the stream is indeed open else throw an exception.
if (FileStream.eof())
throw FileEnd();
char currentchar;
int basepos = 0;
std::string name;
std::vector<char> sequence;
std::vector<int> postn;
currentchar = FileStream.get();
if (FileStream.eof())
throw FileEnd();
if (currentchar != '>')
throw FormatError();
currentchar = FileStream.get();
while(currentchar != '\n' && false == FileStream.eof())
{
name.append(1, currentchar);
currentchar = FileStream.get();
} // done getting names, now let's get the sequence.
currentchar = FileStream.get();
while(currentchar != '>' && false == FileStream.eof())
{
if(currentchar != '\n' && currentchar != ' '){
basepos++;
sequence.push_back(currentchar);
postn.push_back(basepos);
}
currentchar = FileStream.get();
}
if(currentchar == '>')
{
FileStream.unget();
}
return NucleotideSequence(name, postn, sequence);
}
NucleotideSequence2 Sequence_stream::get2()
{
if (FileStream.is_open() == false)
throw StreamClosed(); // Make sure the stream is indeed open else throw an exception.
if (FileStream.eof())
throw FileEnd();
char currentchar;
int basepos = 0;
std::string name;
std::map<int, char> sequence;
currentchar = FileStream.get();
if (FileStream.eof())
throw FileEnd();
if (currentchar != '>')
throw FormatError();
currentchar = FileStream.get();
while(currentchar != '\n' && false == FileStream.eof())
{
name.append(1, currentchar);
currentchar = FileStream.get();
} // done getting names, now let's get the sequence.
currentchar = FileStream.get();
while(currentchar != '>' && false == FileStream.eof())
{
if(currentchar != '\n' && currentchar != ' '){
basepos++;
sequence[basepos] = currentchar;
}
currentchar = FileStream.get();
}
if(currentchar == '>')
{
FileStream.unget();
}
return NucleotideSequence2(name, sequence);
}
然后可以从另一个函数调用这两个函数(它会捕获异常:以防您想知道未捕获的抛出)。
这两个类的区别是一个包含两个向量,而另一个类中包含相同的信息。
我的问题是:第一堂课和构建它的“get”非常快 - 几乎是即时的。 而构建第二个类(带有地图的那个)的“get2”- 明显较慢- 仅超过 5 秒。
为什么用映射构建类比用两个向量构建类慢 - 你应该看到我保持构造函数和两个 get 函数几乎相同,除了向向量添加元素或添加映射的键值对。所以我怀疑重复推回向量比重复添加键值对(即mymap['newkey'] = 'newvalue';)更快、更有效。
如何加快地图版本?
谢谢, 本。
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