将字典与相似键的平均值相结合，Python答案

【问题标题】：Combine Dictionaries With average values for similar keys,Python将字典与相似键的平均值相结合，Python
【发布时间】：2014-08-20 23:22:41
【问题描述】：

我有 2 个字典需要合并。

dict_a = {'key1':[40,70],'key2':[35,76],'key4':[45,90]}  
dict_b = {'key1':[38,72],'key3':[37,89.56],'key4':[47,88]}

我想要第三个字典，它可以结合两者并为相同的键分配平均值。

dict_c ={'key1':[39,71],'key2':[35,76],'key3':[37,89.56],'key4':[46,89]}

请注意以下几点：

1.每个键都有一个包含 2 个元素的列表值。
2.列表中的值可以是int或float。
3.Identical keys的值得到平均like--key1:[39,71]等等

【问题讨论】：

标签： python-2.7 dictionary average

【解决方案1】：

d = {}
for k, v in dict_a.items():
    if k in dict_b:
        val1, val2 =  (v[0]+ dict_b[k][0]) / 2, (v[1] + dict_b[k][1]) / 2 # average sum of ele1 and ele2 in each value list
        d[k] = [val1, val2] # set new value to key
    else:
        d[k] = v # else just add the k,v 

for k,v in dict_b.items(): # add rest of keys from dict_b
    if k not in d: # if key not already in d add it
        d[k] = v
print d

{'key3': [37, 89.56], 'key2': [35, 76], 'key1': [39, 71], 'key4': [46, 89]}

如果您不想再次使用dict_b：

d = {}
for k, v in dict_a.items():
    if k in dict_b:
        val1, val2 = (v[0]+ dict_b[k][0]) / 2, (v[1] + dict_b[k][1]) / 2 # average sum of ele1 and ele2 in each value list
        d[k] = [val1, val2] # set new value to key
        del dict_b[k] # remove key
    else:
        d[k] = v # else just add the k,v

d.update(dict_b) # update with remainder of dict_b

【讨论】：

我也在用python 2.7

【解决方案2】：

代码：

dict_a = {'key1':[40,70],'key2':[35,76],'key4':[45,90]}
dict_b = {'key1':[38,72],'key3':[37,89.56],'key4':[47,88]}

dict_c = {}
for key1, vals1 in dict_a.iteritems():
    try:
        vals2 = dict_b[key1]
        dict_c[key1] = [sum([val1, val2]) / 2 for val1, val2 in zip(vals1, vals2)]
    except KeyError:
        dict_c.update({key1: dict_a[key1]})

for key in dict_b:
    if key not in dict_c:
        dict_c.update({key: dict_b[key]})

print dict_c

输出：

{'key3': [37, 89.56], 'key2': [35, 76], 'key1': [39, 71], 'key4': [46, 89]}

【讨论】：