【发布时间】：2014-07-25 19:34:54
【问题描述】：
当flac文件使用windows的录音机手动录制并使用软件转换器进行转换时，我的程序得到了谷歌的正确响应。
但是当我使用我的程序记录的文件时，我得到了 "{"result":[]}
“来自谷歌。我该怎么办？
这是我的代码：
发件人：
private static void CopyStream(FileStream fileStream, Stream requestStream)
{
var buffer = new byte[32768];
int read;
while ((read = fileStream.Read(buffer, 0, buffer.Length)) > 0)
{
requestStream.Write(buffer, 0, read);
}
}
private static void ConfigureRequest(HttpWebRequest request)
{
request.KeepAlive = true;
request.SendChunked = true;
request.ContentType = "audio/x-flac; rate=44100";
request.UserAgent =
"Mozilla/5.0 (Windows NT 6.2; WOW64) AppleWebKit/535.2 (KHTML, like Gecko) Chrome/15.0.874.121 Safari/535.2";
request.Headers.Set(HttpRequestHeader.AcceptEncoding, "gzip,deflate,sdch");
request.Headers.Set(HttpRequestHeader.AcceptLanguage, "en-GB,en-US;q=0.8,en;q=0.6");
request.Headers.Set(HttpRequestHeader.AcceptCharset, "ISO-8859-1,utf-8;q=0.7,*;q=0.3");
request.Method = "POST";
}
using (var fileStream = new FileStream(@"C:\Users\Ahmad Mustofa\Documents\Visual Studio 2010\Projects\FP\FP\bin\Debug\voice.flac", FileMode.Open))
{
const string requestUrl = "https://www.google.com/speech-api/v2/recognize?output=json&lang=ar-sa&key=AIzaSyBJ6VJ326Rpb23msih2wGhXENEwU1TF1PA&client=chromium&maxresults=1&pfilter=2";
var request = (HttpWebRequest)WebRequest.Create(requestUrl);
ConfigureRequest(request);
var requestStream = request.GetRequestStream();
CopyStream(fileStream, requestStream);
using (var response = request.GetResponse())
{
using (var responseStream = response.GetResponseStream())
{
using (var zippedStream = new GZipStream(responseStream, CompressionMode.Decompress))
{
using (var sr = new StreamReader(zippedStream))
{
var res = sr.ReadToEnd();
state.Text = res;
}
}
}
}
}
wav 录音机：
private void sourceStream_DataAvailable(object sender, NAudio.Wave.WaveInEventArgs e)
{
if (waveWriter == null) return;
waveWriter.WriteData(e.Buffer, 0, e.BytesRecorded);
waveWriter.Flush();
}
fileName = "C:\\Users\\Ahmad Mustofa\\Documents\\Visual Studio 2010\\Projects\\FP\\FP\\bin\\debug\\voice.wav";
int deviceNumber = hardware.SelectedItems[0].Index;
try
{
sourceStream = new NAudio.Wave.WaveIn();
sourceStream.DeviceNumber = deviceNumber;
sourceStream.WaveFormat = new NAudio.Wave.WaveFormat(44100, NAudio.Wave.WaveIn.GetCapabilities(deviceNumber).Channels);
sourceStream.DataAvailable += new EventHandler<NAudio.Wave.WaveInEventArgs>(sourceStream_DataAvailable);
waveWriter = new NAudio.Wave.WaveFileWriter(fileName, sourceStream.WaveFormat);
sourceStream.StartRecording();
}
catch (Exception ex)
{
state.Text = "disini" + ex.Message;
}
flac 转换器：
string inputFile = Path.Combine("wav ", input);
string outputFile = Path.Combine("flac", Path.ChangeExtension(input, ".flac"));
if (!File.Exists(inputFile))
throw new ApplicationException("Input file " + inputFile + " cannot be found!");
WavReader wav = new WavReader(inputFile);
using (var flacStream = File.Create(outputFile))
{
FlacWriter flac = new FlacWriter(flacStream, wav.BitDepth, wav.Channels, wav.SampleRate);
// Buffer for 1 second's worth of audio data
byte[] buffer = new byte[wav.Bitrate / 8];
int bytesRead;
do
{
bytesRead = wav.InputStream.Read(buffer, 0, buffer.Length);
flac.Convert(buffer, 0, bytesRead);
} while (bytesRead > 0);
flac.Dispose();
flac = null;
}
【问题讨论】：
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标签： c# google-api speech-to-text