红宝石岩石，纸，剪刀答案

【问题标题】：Ruby Rock, Paper, Scissors红宝石岩石，纸，剪刀
【发布时间】：2015-04-13 21:03:32
【问题描述】：

我必须为我的 ruby 课程创建这个石头、纸、剪刀游戏的分数更新程序有问题。此分配的目的是让用户输入一个选择，计算机也使用“rand”进行随机选择，并且赢得该轮的人将在每轮结束时显示更新的分数。我遇到的问题是计数器仅使用第一个 if 语句进行更新。该程序可以运行到能够随机选择计算机选项并保存用户响应的程度。因此，所有代码都可以使用分数更新器。任何帮助将不胜感激。

human_score = 0.0
comp_score = 0.0

while true

print "Lets play rock,paper,scissors", "\n"
print "Do you choose rock, paper, or scissors?", "\n"
choice = STDIN.gets.chomp
comp = rand(3)
    if comp == 1
        comp_choice = "rock"
    elsif comp == 2
        comp_choice = "paper"
    else
        comp_choice = "scissors"
    end
print "Computer picked: ", comp_choice, "\n"
print "You picked: ", choice, "\n"
    if human_choice = "rock" && comp_choice = "rock"
        comp_score += 0.5
        human_score += 0.5
        print "The result is a tie", "\n"
    elsif human_choice = "rock" && comp_choice = "paper"
        comp_score += 1
        print "Computer wins", "\n"
    elsif human_choice = "rock" && comp_choice = "scissors"
        human_score += 1
        print "You win", "\n"
    elsif human_choice = "paper" && comp_choice = "rock"
        human_score += 1
        print "You win", "\n"
    elsif human_choice = "paper" && comp_choice = "paper"
        comp_score += 0.5
        human_score += 0.5
        print "Its a tie", "\n"
    elsif human_choice = "paper" && comp_choice = "scissors"
        comp_score += 1
        print "Computer wins", "\n"
    elsif human_choice = "scissors" && comp_choice = "rock"
        comp_score += 1
        print "Computer wins"
    elsif human_choice = "scissors" && comp_choice = "paper"
        human_score += 1
        print "You win"
    else human_choice = "scissors" && comp_choice = "scissors"
        human_score += 0.5
        comp_score += 0.5
        print "Its a tie"
    end
print "The computers score is: ", comp_score, "\n"
print "Your score is: ", human_score, "\n"

end

【问题讨论】：

您用于比较选择的if 语句都使用=，它已成功分配给这些变量；将这些更改为==。

标签： ruby

【解决方案1】：

您正在重新分配变量的值，而不是检查是否相等。

您的版本：

if human_choice = "rock" && comp_choice = "rock"

这会将human_choice 的值设置为“rock”，与comp_choice 相同。永远都是真的。

正确版本：

if human_choice == "rock" && comp_choice == "rock"

【讨论】：

【解决方案2】：

另外，您将从键盘读取的值分配给choice

choice = STDIN.gets.chomp

您正在使用human_choice 来验证案例。

【讨论】：

【解决方案3】：

思考这个：

human_score = 0.0
comp_score = 0.0

while true

  puts "Lets play rock, paper, scissors"
  puts "Do you choose rock, paper, or scissors?"
  human_choice = STDIN.gets.chomp

  comp_choice = %w[scissors rock paper][rand(3)]

  puts "Computer picked: #{ comp_choice }"
  puts "You picked: #{ human_choice }"

  msg = case [human_choice, comp_choice]
  when ['rock', 'rock'], ['paper', 'paper'], ['scissors', 'scissors']
    comp_score += 0.5
    human_score += 0.5
    'The result is a tie'
  when ['rock', 'scissors'], ['paper', 'rock'], ['scissors', 'paper']
    human_score += 1
    'You win'
  when ['paper', 'scissors'], ['scissors', 'rock'], ['rock', 'paper']
    comp_score += 1
    'Computer wins'
  end

  puts msg
  puts "The computer's score is: #{ comp_score }"
  puts "Your score is: #{ human_score }"

end

它是使用惯用的 Ruby 编写的。

【讨论】：