如何将数组插入数据库而不会出错：数组到字符串的转换[重复]

Question

在 m 应用程序中，我有一个包含数据的表单，用于将数据插入 2 个表：付款人和配偶，付款人有很多配偶。在我的 PayerController 我有

public function store(CreatePayerRequest $request)
    { 
        $input = $request->all();
        $payer = $this->payerRepository->create($input);
        {

我有

dd($request->all())

并得到以下结果，表明我的数组从我的输入表单成功传递。

array:34 [▼
  "_token" => "LDdsaesoaRlKmM0URHVxQqyiJHdrPhLz3lmYQs6V"
  "added_on" => "2020-06-28 11:07:39"
  "user_id" => array:2 [▼
    0 => "Auth::user()->id"
    1 => "Auth::user()->id"
  ]
  "ass_code" => "508063"
  "title" => "Mr"
  "surname" => "PLC"
  "firstname" => "ZENITH"
  "othernames" => "A,"
  "dob" => "2020-06-28 12:08:59"
  "address" => "43"
  "street" => "Old School"
  "town" => "Umuguma"
  "lga" => "Okigwe"
  "state" => "Imo"
  "nationality" => "Nigerian"
  "occupation" => "Civil Servant"
  "vocation" => "Employment"
  "phone" => "8035514494"
  "email" => "ugo@yahoo.com"
  "income_status" => "Yes"
  "allowance_status" => "No"
  "acc_status" => "1"
  "assess_status" => "0"
  "approve_status" => "0"
  "payment_status" => "0"
  "authorize_status" => "0"
  "marital_stat" => "Married"
  "spouse_name" => array:2 [▼
    0 => "Tony"
    1 => "Nkechi"
  ]
  "spouse_dob" => array:2 [▶]
  "spouse_emplbiz_add" => array:2 [▼
    0 => "nA"
    1 => "nA"
  ]
  "spose_income" => array:2 [▼
    0 => "50000"
    1 => "50000"
  ]
  "child_status" => "Yes"
  "vehicle_status" => "Yes"
  "assets_status" => "Nigeria"
]

我的问题是，当我发送带有配偶数组的表单时，它给了我错误：

错误异常 数组到字符串的转换

我尝试过各种代码，例如

代码 1

 $payer->spouses()->create();
       

代码 2

 $spouses = Spouse::find($payer->id);
            foreach($request->spouses as $spouse){
                $payer->spouses()->create([
                    'user_id' => Auth::user()->id,
                    'spouse_occupation'=>NA,
                    'spouse_name'=>$spouse_name,
                    'spouse_dob'=>$spouse_dob,
                    'spouse_emplbiz_add'=>$spouse_emplbiz_add]);

代码 3：

$spouses = new Spouse();
                $spouses->user_id = Auth::user()->id;
                $spouses->payer_id = $payer->id;
                $spouses->spouse_occupation='NA';
                $spouses->spouse_name = $request->input('spouse_name');
                $spouses->spouse_dob = $request->input('spouse_dob');
                $spouses->spouse_emplbiz_add = $request->input('spouse_emplbiz_add');
                $spouses->spose_income = $request->input('spose_income');
                $spouses->save();

我不断收到同样的错误。

谁能告诉我如何在插入付款人的同时将数组中的配偶详细信息插入我的数据库。

在我正在关注的教程中，导师发送了以下代码，但它对我不起作用：

foreach($request->spouses as $spouse){
payer->spouses()->(['name'='$spouse'])

我认为这是因为他只有一个输入字段。但就我而言，我最多有 4 个。

我的配偶输入是一个带有以下代码的 livewire 组件

@foreach($spouses as $spouse)
   <div class="col-md-10 d-flex">
        
 {!! Form::hidden('user_id[]', 'Auth::user()->id',array(
    'class' => 'form-control col-3',
    'id' => 'user_id[]',
))  !!}
   {!! Form::text('spouse_name[]', '',array(
        'class' => 'form-control col-3',
        'id' => 'spouse_name[]',
        'placeholder' => 'Spouse name',
    ))  !!}
    {!! Form::text('spouse_dob[]', '',array(
        'class' => 'form-control col-3',
        'id' => 'spouse_dob[]',
        'placeholder' => 'Spouse Age',
    ))  !!}
    {!! Form::text('spouse_emplbiz_add[]', '',array(
        'class' => 'form-control col-3',
        'id' => 'spouse_emplbiz_add[]',
        'placeholder' => 'Work Address',
    ))  !!}
    {!! Form::text('spose_income[]', '',array(
        'class' => 'form-control col-3',
        'id' => 'spose_income[]',
        'placeholder' => 'Gross Income',
    )) !!}
    <span class="btn btn-default fa fa-times text-danger padding:2" 
    wire:click="remove({{$loop->index}})"></span>        
</div>
    @endforeach

Answer 1

您的错误准确地描述了您的问题。您正在尝试保存数组，因此出现此错误。

$spouses->spouse_name = $request->input('spouse_name');
            $spouses->spouse_dob = $request->input('spouse_dob');
            $spouses->spouse_emplbiz_add = $request->input('spouse_emplbiz_add');
            $spouses->spose_income = $request->input('spose_income');

所有这些数据都是数组。

"spouse_name" => array:2 [▼
  0 => "Tony"
  1 => "Nkechi"
]
"spouse_dob" => array:2 [▶]
"spouse_emplbiz_add" => array:2 [▼
  0 => "nA"
  1 => "nA"
]
"spose_income" => array:2 [▼
  0 => "50000"
  1 => "50000"
]

如果你的表中这些列的类型是json，那么你应该这样保存。

$spouses->spouse_name = json_encode($request->input('spouse_name'));
    $spouses->spouse_dob = json_encode($request->input('spouse_dob'));
    $spouses->spouse_emplbiz_add = json_encode($request->input('spouse_emplbiz_add'));
    $spouses->spose_income = json_encode($request->input('spose_income'));

Answer 2

您可以为付款人和配偶模型尝试类似的方法......

    $payer = new Payer();
    $payer->property =  $request->property;
    $payer->save();

if(count($request->spouse_name) > 0){
    for($i = 0; $i < count($request->spouse_name); $i++){

        $object = new Spouse();
        $object->payer_id = $payer->id
        $object->spouse_name= $request->spouse_name[$i];
        $object->save();

   } 
}