【发布时间】:2016-09-16 11:38:41
【问题描述】:
以下内容应按单圈时间升序对一组车手进行排序:
function sortDrivers($a, $b)
{
if (floatval($a->fastestLap) === floatval($b->fastestLap)) {
return 0;
}
return floatval($a->fastestLap) < floatval($b->fastestLap) ? -1 : 1;
}
Log::info("Before:");
foreach($drivers as &$driver){
Log::info($driver->driverCode . " - " . floatval($driver->fastestLap));
}
usort($drivers, "sortDrivers");
$position = 0;
foreach($drivers as &$driver){
$driver->position = ++$position;
$driver->save();
}
Log::info("After:");
foreach($drivers as &$driver){
Log::info($driver->driverCode . " - " . floatval($driver->fastestLap) . " - " . $driver->position);
}
这个的实际输出看起来像:
Before:
Mark - 112.2
Roger - 108.77
Pete - 110.038
Gary - 109.49
Sid - 111.742
Rod - 87.082
Bob - 110.404
Eric - 112.482
Will - 113.478
Nigel - 0
Harry - 110.01
Paul - 112.887
Victor - 109.182
Matt - 109.987
Clive - 109.975
Sol - 109.23
Olly - 0
Ben - 0
Craig - 114.241
Andy - 96.399
Adam - 93.177
Kel - 110.766
After:
Rod - 87.082 - 1
Adam - 93.177 - 2
Paul - 112.887 - 3
Roger - 108.77 - 4
Bob - 110.404 - 5
Mark - 112.2 - 6
Will - 113.478 - 7
Gary - 109.49 - 8
Pete - 110.038 - 9
Harry - 110.01 - 10
Matt - 109.987 - 11
Craig - 114.241 - 12
Eric - 112.482 - 13
Sid - 111.742 - 14
Kel - 110.766 - 15
Clive - 109.975 - 16
Sol - 109.23 - 17
Victor - 109.182 - 18
Andy - 96.399 - 19
Olly - 0 - 20
Nigel - 0 - 21
Ben - 0 - 22
虽然明显有增加单圈时间的趋势,但有几位车手走错了地方。
为什么?
【问题讨论】:
-
floatval($a->fastestLap) === floatval($b->fastestLap)是一个失败的赌注。永远不要期望两个浮点值相等。将它们的差值的绝对值与一个小阈值进行比较,并在未超过阈值时认为它们相等。但是,这不是您在此处暴露的行为的原因。 -
我无法使用您的“sortDrivers”功能复制您的行为 - 它可以工作;-/ 不管怎样,这似乎可以满足您的需求:eval.in/643912。即零次排序最后