引用 Laravel 中的另一个模型

Question

刚刚在 Laravel (5.4) 中完成了我正在开发的项目的“朋友”系统。在我的情况下，我称它们为“连接”。一切正常，我现在正在尝试稍微清理一下。

从一开始，按照教程和 SO 答案，我将每个方法都放在了我的 User 模型中（这并不是那么不好：连接与用户相关）。但我想清理所有与我的连接相关的内容并将其放入一个名为 Connection 的模型中。

1. User 模型是否应该处理与连接相关的所有事情，或者我的清洁愿望是有道理的，Connection 模型是合法的？
2. 如何实现以下代码？如何引用User 现在我不在课堂上，$this 变得毫无意义？

连接模型

namespace App;

use Illuminate\Support\Facades\Auth;
use Illuminate\Foundation\Auth\User as Authenticatable;

class Connection extends Authenticatable
{
    const PENDING = 0;
    const ACCEPTED = 1;
    const REJECTED = 2;
}

用户模型

namespace App;

use Illuminate\Support\Facades\Auth;
use Illuminate\Foundation\Auth\User as Authenticatable;

class User extends Authenticatable
{

    // Get connections the user initiated by himself
    public function connectionsOfOwner() {
        return $this->belongsToMany(User::class, 'connections', 'user_id', 'connection_id')->withPivot('status');
    }

    // Get connections the user has been invited to
    public function connectionsOf() {
        return $this->belongsToMany(User::class, 'connections', 'connection_id', 'user_id')->withPivot('status');
    }

    // Accessor allowing to call $this->connections
    public function getConnectionsAttribute() {
        if (!array_key_exists('connections', $this->relations)) {
            $this->loadConnections();
        }

        return $this->getRelation('connections');
    }

    // Check if a Laravel relation named "connection" exists
    protected function loadConnections() {
        if (!array_key_exists('connections', $this->relations)) {
            $this->setRelation('connections', $this->mergeConnections());
        }
    }

    // Merge "connectionsOfOwner" and "connectionsOf"
    protected function mergeConnections() {
        return $this->connectionsOfOwner->merge($this->connectionsOf);
    }

    // Get pending connections
    public function getPendingConnections() {
        $filtered = $this->connections->filter(function ($value, $key) {
            if ($value->pivot->status == 0) {
                return $value;
            }
        });

        return $filtered;
    }

    // Get accepted connections
    public function getAcceptedConnections() {
        $filtered = $this->connections->filter(function ($value, $key) {
            if ($value->pivot->status == 1) {
                return $value;
            }
        });

        return $filtered;
    }

    // Add a connection
    public function addConnection($user) {
        $this->connectionsOfOwner()->attach($user->id);
    }

    // Accept a connection
    public function acceptConnection($user) {
        $this->connectionsOf()->syncWithoutDetaching([$user->id => ['status' => Connection::ACCEPTED]]);
        $this->connectionsOfOwner()->attach($user->id, ['status' => Connection::ACCEPTED]);
    }

    // Remove a connection
    public function removeConnection($user) {
        $this->connectionsOfOwner()->detach($user->id);
        $this->connectionsOf()->detach($user->id);
    }

}

Answer 1

您可能可以跳过连接模型并将该功能保留在您在用户模型中使用的特征“HasConnections”中。

Jeffrey Way 在 Laracon2017 中简要介绍了这种方法：https://streamacon.com/video/laracon-us-2017/day-2-jeffrey-way

祝你好运！