在pyowm中找不到城市时如何创建输出？答案

【问题标题】：How to create an output when city isn't found in pyowm?在pyowm中找不到城市时如何创建输出？
【发布时间】：2021-09-25 12:37:36
【问题描述】：

如果找不到国家/地区（例如，用户写错了城市），如何在终端上创建自定义输出？

默认输出是错误码：

raise exceptions.NotFoundError('无法找到资源') pyowm.commons.exceptions.NotFoundError: 找不到资源

我希望输出类似于：

抱歉，我无法找到您搜索的城市。请重试...

这是我目前的代码：

import pyowm

owm = pyowm.OWM('api code')
weather = True

while weather == True:
            weather_input = input('Enter the name of the city you want me to search - ')
            mgr = owm.weather_manager()
            weather_city1 = mgr.weather_at_place(weather_input)
            w = weather_city1.weather
            print('Weather in ' + weather_input + ' - ' + str(w.temperature('celsius')))

【问题讨论】：

试试try:\n 'your whole code goes here' \nexcept pyowm.commons.exceptions.NotFoundError: print('Sorry, I was unable to find the city you searched for. Please try again...')

标签： python python-3.x openweathermap

【解决方案1】：

尝试异常处理！继承自 C 派生语言的一个不错的 Python 特性：

from pyowm import OWM
from pyowm.commons.exceptions import NotFoundError

owm = OWM('api code')
mgr = owm.weather_manager()

while True:
            weather_input = input('Enter the name of the city you want me to search - ')
            try:
                weather_city1 = mgr.weather_at_place(weather_input)
                w = weather_city1.weather
                print('Weather in ' + weather_input + ' - ' + str(w.temperature('celsius')))
            except NotFoundError:
                print('Sorry, I was unable to find the city you searched for. Please try again...')

【讨论】：