【发布时间】:2018-01-18 17:04:01
【问题描述】:
我正在尝试使用他们的auth UID 作为子节点将用户添加到 Firebase 中的实时数据库。
我一直使用这个问题作为指导:
当我在调试模式下运行项目时,会添加用户。但是,当我正常运行该应用程序时,它会崩溃。我得到的错误是空指针异常。
这是我的代码:
public class RegisterUser extends AppCompatActivity {
private static final String TAG = "RegisterUser";
private FirebaseAuth mAuth;
private FirebaseAuth.AuthStateListener mAuthListener;
private FirebaseUser fbUser =null;
private DatabaseReference mFirebaseDatabase;
User user;
private EditText mEmail, mPassword;
private RadioButton rManager, rPlayer;
private Button mRegister;
private ProgressBar mProgressbar;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_register_user);
mEmail = (EditText) findViewById(R.id.email_field);
mPassword = (EditText) findViewById(R.id.password_field);
rManager = (RadioButton) findViewById(R.id.managerBtn);
rPlayer = (RadioButton) findViewById(R.id.playerBtn);
mRegister = (Button) findViewById(R.id.btnSignIn);
mProgressbar = (ProgressBar) findViewById(R.id.progressBar);
mAuth = FirebaseAuth.getInstance();
mRegister.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
String email = mEmail.getText().toString();
String password = mPassword.getText().toString();
if (TextUtils.isEmpty(email)) {
Toast.makeText(getApplicationContext(), "Enter email address!", Toast.LENGTH_SHORT).show();
return;
}
if (TextUtils.isEmpty(password)) {
Toast.makeText(getApplicationContext(), "Enter password!", Toast.LENGTH_SHORT).show();
return;
}
if (password.length() < 6) {
Toast.makeText(getApplicationContext(), "Password too short, enter minimum 6 characters!", Toast.LENGTH_SHORT).show();
return;
}
if (!rManager.isChecked() && !rPlayer.isChecked()) {
Toast.makeText(RegisterUser.this, "You must select either player or manager", Toast.LENGTH_LONG).show();
}
mProgressbar.setVisibility(View.VISIBLE);
String type = "";
//radio buttons
if (rManager.isChecked()) {
type = "Manager";
} else if (rPlayer.isChecked()) {
type = "Player";
}
mFirebaseDatabase = FirebaseDatabase.getInstance().getReference("User");
String userId = mFirebaseDatabase.push().getKey();
User user = new User(email, password, type);
mAuth.createUserWithEmailAndPassword(email, password);
fbUser = FirebaseAuth.getInstance().getCurrentUser();
mFirebaseDatabase.child(fbUser.getUid()).setValue(user);
mProgressbar.setVisibility(View.GONE);
startActivity(new Intent(RegisterUser.this, HomePage.class));
@Override
protected void onResume() {
super.onResume();
mProgressbar.setVisibility(View.GONE);
}
public void onLogIn(View v) {
Intent i = new Intent(this, MainActivity.class);
//i.putExtra(key_1, userName.getText().toString()); //get id for training and display details in full
startActivity(i);
}
}
错误:
01-18 17:01:42.331 3781-3781/com.example.cianm.fyp2018v2 E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.example.cianm.fyp2018v2, PID: 3781
java.lang.NullPointerException
at com.example.cianm.fyp2018v2.RegisterUser$1.onClick(RegisterUser.java:142)
at android.view.View.performClick(View.java:4463)
at android.view.View$PerformClick.run(View.java:18789)
at android.os.Handler.handleCallback(Handler.java:808)
at android.os.Handler.dispatchMessage(Handler.java:103)
at android.os.Looper.loop(Looper.java:193)
at android.app.ActivityThread.main(ActivityThread.java:5299)
at java.lang.reflect.Method.invokeNative(Native Method)
at java.lang.reflect.Method.invoke(Method.java:515)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:829)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:645)
at dalvik.system.NativeStart.main(Native Method)
任何帮助将不胜感激。
【问题讨论】:
-
RegisterUser 第 142 行是什么,正如您的堆栈跟踪所建议的那样?
-
mFirebaseDatabase.child(fbUser.getUid()).setValue(user); @DougStevenson
-
createUserWithEmailAndPassword()是一个异步操作。您不能在以下语句中调用getCurrentUser()并期望得到有效结果。 -
@BobSnyder 好的,谢谢鲍勃,你知道在哪里打电话来实现链接问题中所做的事情吗? link
标签: java android firebase firebase-realtime-database firebase-authentication