在 Swift 中使用 GMSAddress 和 GMSGeocoder 从地址返回坐标答案

【问题标题】：Using GMSAddress and GMSGeocoder to return Coordinates from Address in Swift在 Swift 中使用 GMSAddress 和 GMSGeocoder 从地址返回坐标
【发布时间】：2015-02-17 08:40:43
【问题描述】：

有没有办法在 iOS Swift 中使用 GMS 从输入的地址字符串中获取坐标？我可以找到从坐标返回地址的示例（反向地理编码？），但不是相反。谷歌提供这项服务吗？首先解析输入的地址字符串，返回最合适的实际地址，最后返回坐标。请提供一个简单的例子，或者指出我正确的方向。问候，克里斯

【问题讨论】：

标签： ios swift geocoding reverse-geocoding

【解决方案1】：

自 2015 年 6 月起，GMS iOS SDK 不再直接公开此功能。但是，有两种方法可以得到它。第一个是使用 Google Maps Web API。

let baseURLGeocode = "https://maps.googleapis.com/maps/api/geocode/json?"

func geocodeAddress(address: String!, withCompletionHandler completionHandler: ((status: String, success: Bool) -> Void)) {

    if let lookupAddress = address {

        var geocodeURLString = baseURLGeocode + "address=" + lookupAddress
        geocodeURLString = geocodeURLString.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!

        let geocodeURL = NSURL(string: geocodeURLString)

        dispatch_async(dispatch_get_main_queue(), { () -> Void in
            let geocodingResultsData = NSData(contentsOfURL: geocodeURL!)

            var error: NSError?
            let dictionary: Dictionary<NSObject, AnyObject> = NSJSONSerialization.JSONObjectWithData(geocodingResultsData!, options: NSJSONReadingOptions.MutableContainers, error: &error) as Dictionary<NSObject, AnyObject>

            if (error != nil) {
                println(error)
                completionHandler(status: "", success: false)
            }
            else {
                // Get the response status.
                let status = dictionary["status"] as String

                if status == "OK" {
                    let allResults = dictionary["results"] as Array<Dictionary<NSObject, AnyObject>>
                    self.lookupAddressResults = allResults[0]

                    // Keep the most important values.
                    self.fetchedFormattedAddress = self.lookupAddressResults["formatted_address"] as String
                    let geometry = self.lookupAddressResults["geometry"] as Dictionary<NSObject, AnyObject>
                    self.fetchedAddressLongitude = ((geometry["location"] as Dictionary<NSObject, AnyObject>)["lng"] as NSNumber).doubleValue
                    self.fetchedAddressLatitude = ((geometry["location"] as Dictionary<NSObject, AnyObject>)["lat"] as NSNumber).doubleValue

                    completionHandler(status: status, success: true)
                }
                else {
                    completionHandler(status: status, success: false)
                }
            }
        })
    }
    else {
        completionHandler(status: "No valid address.", success: false)
    }
}

你可以在这里找到这个方法的完整描述：http://www.appcoda.com/google-maps-api-tutorial/

第二种方法是使用苹果原生的CoreLocation框架

func geoLocate(address:String!){
let gc:CLGeocoder = CLGeocoder()

gc.geocodeAddressString(address, completionHandler: { (placemarks: [AnyObject]!, error: NSError!) -> Void in
    let pm = placemarks as! [CLPlacemark]
    if (placemarks.count > 0){
        let p = pm[0]

        var myLatitude = p.location.coordinate.latitude
        var myLongtitude = p.location.coordinate.longitude

        //do your stuff
    }
})
}

编辑：Swift 4.2

func geoLocate(address:String!){
        let gc:CLGeocoder = CLGeocoder()
        gc.geocodeAddressString(address) { (placemarks, error) in
            if ((placemarks?.count)! > 0){
                let p = placemarks![0]
                print("Lat: \(p.location?.coordinate.latitude) Lon: \(p.location?.coordinate.longitude)")
            }

    }
}

【讨论】：