【问题标题】:How would i retrieve the postal code from an xml response from google geocoding api?我如何从谷歌地理编码 api 的 xml 响应中检索邮政编码?
【发布时间】:2021-06-10 03:55:10
【问题描述】:

我目前正在做一个 MVC 项目,需要根据用户地址获取邮政编码。我已经能够成功获取经纬度,但不知道如何从 xml 响应中提取邮政编码。

这是他们在 api 文档页面上使用的示例 XML。

 <GeocodeResponse>
 <status>OK</status>
 <result>
  <type>street_address</type>
  <formatted_address>1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA</formatted_address>
  <address_component>
   <long_name>1600</long_name>
   <short_name>1600</short_name>
   <type>street_number</type>
  </address_component>
  <address_component>
   <long_name>Amphitheatre Pkwy</long_name>
   <short_name>Amphitheatre Pkwy</short_name>
   <type>route</type>
  </address_component>
  <address_component>
   <long_name>Mountain View</long_name>
   <short_name>Mountain View</short_name>
   <type>locality</type>
   <type>political</type>
  </address_component>
  <address_component>
   <long_name>San Jose</long_name>
   <short_name>San Jose</short_name>
   <type>administrative_area_level_3</type>
   <type>political</type>
  </address_component>
  <address_component>
   <long_name>Santa Clara</long_name>
   <short_name>Santa Clara</short_name>
   <type>administrative_area_level_2</type>
   <type>political</type>
  </address_component>
  <address_component>
   <long_name>California</long_name>
   <short_name>CA</short_name>
   <type>administrative_area_level_1</type>
   <type>political</type>
  </address_component>
  <address_component>
   <long_name>United States</long_name>
   <short_name>US</short_name>
   <type>country</type>
   <type>political</type>
  </address_component>
  <address_component>
   <long_name>94043</long_name>
   <short_name>94043</short_name>
   <type>postal_code</type>
  </address_component>
  <geometry>
   <location>
    <lat>37.4217550</lat>
    <lng>-122.0846330</lng>
   </location>
   <location_type>ROOFTOP</location_type>
   <viewport>
    <southwest>
     <lat>37.4188514</lat>
     <lng>-122.0874526</lng>
    </southwest>
    <northeast>
     <lat>37.4251466</lat>
     <lng>-122.0811574</lng>
    </northeast>
   </viewport>
  </geometry>
  <place_id>ChIJ2eUgeAK6j4ARbn5u_wAGqWA</place_id>
  >plus_code<
   >global_code<849VCWC8+W5>/global_code<
   >compound_code<CWC8+W5 Mountain View, California, United States>/compound_code<
 >/plus_code<
 </result>
</GeocodeResponse>

这是我在控制器中用于获取信息的代码:

    string address = "Users Address(HIDDEN)";

    string requestUri = string.Format("https://maps.googleapis.com/maps/api/geocode/xml?address={0}&sensor=false&key=HIDDEN", address);

    WebRequest request = WebRequest.Create(requestUri);
    WebResponse response = request.GetResponse();

    XmlDocument document = new XmlDocument();

    document.Load(requestUri);

    string status = document.SelectSingleNode("/GeocodeResponse/status").InnerText;
    string lat = "", lng = "", postal = "";

    if (status == "OK")
    {
        lat = document.SelectSingleNode("/GeocodeResponse/result/geometry/location/lat").InnerText;
        lng = document.SelectSingleNode("/GeocodeResponse/result/geometry/location/lng").InnerText;
        postal = document.SelectSingleNode("/GeocodeResponse/result/address_component/long_name").InnerText;
    }

    return ($"Latitude: {lat} / Longitude: {lng} / {postal}");

我们将不胜感激。

【问题讨论】:

    标签: model-view-controller google-api geocoding


    【解决方案1】:

    我一直在做更多的挖掘并找到了答案。基本上必须遍历 address_component 节点,直到我到达 address_component 的 postal_code 子节点并获得具有 postal 的 long_name 子节点。这是我的解决方案:

    XmlNodeList nlist = document.SelectNodes("/GeocodeResponse/result/address_component");
    
                    foreach(XmlNode node in nlist)
                    {
                        var longName = node.ChildNodes.Item(0).InnerText;
                        var shortName = node.ChildNodes.Item(1).InnerText;
                        var zipType = node.ChildNodes.Item(2).InnerText;
    
                        if(zipType == "postal_code")
                        {
                            postal = longName;
                        }
                    }
    

    【讨论】:

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