【发布时间】:2014-09-18 17:04:16
【问题描述】:
我有以下代码
HTML:
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False">
<Columns>
<asp:TemplateField HeaderText="Checkbox">
<ItemTemplate>
<asp:CheckBox ID="chkb" runat="server" />
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="ID" Visible="false">
<ItemTemplate>
<asp:Label ID="lblId" runat="server" Text='<%# Eval("Id")%>'>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Name">
<ItemTemplate>
<asp:Label ID="lblName" runat="server" Text='<%# Eval("Name")%>'>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Country">
<ItemTemplate>
<asp:Label ID="lblCountry" runat="server" Text='<%# Eval("Country")%>'>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
后面的代码:
Protected Sub btnExcel_Click(sender As Object, e As EventArgs) Handles btnExcel.Click
Debug.WriteLine("Clicked")
For Each row As GridViewRow In GridView1.Rows
Dim chk As CheckBox = row.FindControl("chkb")
If chk.Checked Then
Dim lbl As Label = row.FindControl("lblId")
Debug.WriteLine(chk.Checked)
Debug.WriteLine(lbl.Text)
End If
Next
End Sub
复选框部分有问题吗?因为我可以获得输出“Clicked”,但似乎无法获得
的输出Debug.WriteLine(chk.Checked)
Debug.WriteLine(lbl.Text)
另外,我在调试时无法获取 chk.Checked 的值。
【问题讨论】:
-
@Amignos 确保回发
-
@Thirisangu 什么是回发以及如何回发?抱歉,我是 vb.net 的新手
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@Amignos IF Not IsPostBack Then GridBind()// 绑定Grid View End IF的方法