如何从json字符串中获取值

Question

我有一个 json 字符串字符串，我想从中获取值。它是密钥对形式，所以我想要每个密钥的值。

我试图获取这些值，但我没有得到它。

Json 字符串是这样的：

{
    "document": {
        "xmlns:xsi": "http:\/\/www.w3.org\/2001\/XMLSchema-instance",
        "xsi:schemaLocation": "http:\/\/ocrsdk.com\/schema\/recognizeard-1.0.xsd http:\/\/ocrsdk.com\/schema\/recognized-1.0.xsd",
        "xmlns": "http:\/\/ocrsdk.com\/schema\/recognize-1.0.xsd",
        "businessCard": {
            "imageRotation": "noRotation",
            "field":

                [{
                "type": "Name",
                "value": "Rafcev B. Agnrwal"
            }, {
                "type": "Company",
                "value": "VJ>"
            }, {
                "type": "Text",
                "value": "Dr. Rafcev B. Agnrwal\nMOB 0324%\nun\n) AOM*. founts. sso\nVJ>\nT"
            }]
        }
    }
}

我想获取“姓名”、“地址”、“公司”等值。

我试着变成这样：

JSONArray array;
if(mIntent.getStringExtra("jsonString") != null) {
            Log.d("json", mIntent.getStringExtra("jsonString"));

        try {
            JSONObject object = new JSONObject(mIntent.getStringExtra("jsonString"));

            array = object.getJSONArray("field");

            for (int i = 0; i < array.length(); i++) {
                JSONObject subObject1 = array.getJSONObject(i);

                edt_FirstName.setText(object.getString("Name"));
            }

        } catch (JSONException e) {

}

谁能帮帮我？谢谢。。

编辑：

我试图检查这样的值：

for (int i = 0; i < array.length(); i++) {
    JSONObject subObject1 = array.getJSONObject(0);

    String type = subObject1.getString("type");
    String value = subObject1.getString("value");
    if (type.equals("Name")) {
        edt_FirstName.setText(value);
    }
    if(type.equals("Address"))
    {
        edt_address.setText(value);
    }
    if(type.equals("Company"))
    {
        edt_company.setText(value);
    }
    if(type.equals("Mobile"))
    {
        edt_Mobile.setText(value);
    }
}

我想从字段数组中获取所有值并设置为文本视图，但我只获取名称值而不获取其他值。

我也可以像 Mobile 一样获得两倍的字段，所以我想结合 Mobile 值并显示它。

Answer 1

所以你的 json 对象如下：

{
    "document": {
        "xmlns:xsi": "http:\/\/www.w3.org\/2001\/XMLSchema-instance",
        "xsi:schemaLocation": "http:\/\/ocrsdk.com\/schema\/recognizeard-1.0.xsd http:\/\/ocrsdk.com\/schema\/recognized-1.0.xsd",
        "xmlns": "http:\/\/ocrsdk.com\/schema\/recognize-1.0.xsd",
        "businessCard": {
            "imageRotation": "noRotation",
            "field":

                [{
                "type": "Name",
                "value": "Rafcev B. Agnrwal"
            }, {
                "type": "Company",
                "value": "VJ>"
            }, {
                "type": "Text",
                "value": "Dr. Rafcev B. Agnrwal\nMOB 0324%\nun\n) AOM*. founts. sso\nVJ>\nT"
            }]
        }
    }
}

你首先需要得到“document”为JSONObject，然后得到“businessCard”为JSONObject，然后你可以得到“field”为JSONArray：

if(mIntent.getStringExtra("jsonString") != null) {
    Log.d("json", mIntent.getStringExtra("jsonString"));

    try {
        JSONObject object = new JSONObject(mIntent.getStringExtra("jsonString"));

        JSONArray array = object.getJSONObject("document").getJSONObject("businessCard").getJSONArray("field");

        for (int i = 0; i < array.length(); i++) {
            JSONObject subObject = array.getJSONObject(i);

            String type = subObject.getString("type");
            String value = subObject.getString("value");
            if (type.equals("Name")) {
                    String prevValue = edt_FirstName.getText();
                    edt_FirstName.setText((TextUtils.isEmpty(prevValue) ? "" : prevValue + ",") + value);
            }
        }

    } catch (JSONException e) { }
}

Answer 2

试试这个代码，希望对你有帮助。

try
{
    JSONObject jsonObject = new JSONObject();
    JSONObject documentObject = jsonObject.getJSONObject("document");
    JSONObject businessCardObject = documentObject.getJSONObject("businessCard");

    String imgRotation = businessCardObject.getString("imageRotation");
    JSONArray array = businessCardObject.getJSONArray("field");

    for (int i = 0; i < array.length() ; i++)
    {
        JSONObject arrObj = array.getJSONObject(i);

        String type = arrObj.getString("type");
        String value = arrObj.getString("value");

        Log.e(TAG, "type=="+type);
        Log.e(TAG, "value=="+value);
    }
}
catch (Exception ex)
{
    ex.printStackTrace();
}

Answer 3

这里是代码

private void convertJsonToDto(String jsonNewString) {
    JSONObject jsonObj = new JSONObject(jsonNewString);
    String RecordLocator = (String) jsonObj.get("obj");
    String FirstName = (String) jsonObj.getJSONObject("Customer").get("FirstName");
    JSONArray array = new JSONObject(jsonNewString).getJSONArray("Array");
    JSONObject jsonObject = array.getJSONObject(0);
    String str = jsonObject.getString("object");
}