【发布时间】:2013-11-18 14:54:03
【问题描述】:
我已经成功地将城市飞艇推送通知集成到我的安卓应用程序中。我在这里遇到了一个问题,即第一次启动时 apID 变为空,然后在第二次启动时,apId 正确。
这就是我获取 apId 的方式:
String apid = PushManager.shared().getAPID();
这是我用过的类:
public class MyApplication extends Application {
public static SharedPreferences PREFS_TOKEN;
public static final String PREFERENCE = "UrbanAirship";
public static String tokenKey;
@Override
public void onCreate(){
AirshipConfigOptions options = AirshipConfigOptions.loadDefaultOptions(this);
UAirship.takeOff(this, options);
PushManager.enablePush();
Logger.logLevel = Log.VERBOSE;
// use CustomPushNotificationBuilder to specify a custom layout
CustomPushNotificationBuilder nb = new CustomPushNotificationBuilder();
nb.statusBarIconDrawableId = R.drawable.paw;// custom status bar icon
nb.layout = R.layout.notification;
nb.layoutIconDrawableId = R.drawable.paw;// custom layout icon
nb.layoutIconId = R.id.icon;
nb.layoutSubjectId = R.id.subject;
nb.layoutMessageId = R.id.message;
// customize the sound played when a push is received
// nb.soundUri =
// Uri.parse("android.resource://"+this.getPackageName()+"/"
// +R.raw.cat);
String apid = PushManager.shared().getAPID();
Logger.info("My Application onCreate - App APID: " + apid);
PREFS_TOKEN = this.getSharedPreferences(PREFERENCE,
Context.MODE_PRIVATE);
Editor edit = PREFS_TOKEN.edit();
if (apid != null && apid != "") {
edit.putString(PREFERENCE, apid);
edit.commit();
} else {
edit.putString(PREFERENCE, apid);
edit.commit();
}
tokenKey = PREFS_TOKEN.getString(PREFERENCE, "");
System.out.println("---------- - App APID: " + tokenKey);
PushManager.shared().setNotificationBuilder(nb);
PushManager.shared().setIntentReceiver(IntentReceiver.class);
}
}
我还有一个 IntentReceiver 类。任何帮助表示赞赏。
【问题讨论】:
-
获取 null apid 时是否收到任何错误/消息?
-
不是错误消息,只是在第一次启动时为空。
标签: android null urbanairship.com