想在 bash 脚本中打印 PPID 和 pid [关闭]

Question

在下面的程序中，我可以打印出显着的ppid来打印pid，

我想知道答案，pid很重要所以我要打印出来

#! /bin/bash

echo " a.display PTD of parent and child "
echo " b. copy the file content "
echo " enter your choice "
read ch

case $ch in

a)
    echo " parent pid is $PPID"
    echo " pid is $PID"
;;

b)
    echo "enter a source file"
    read f1
    echo "enter destination file "
    read f2

    if [ -f $f1 ]
    then 
      cp $f1 $f2
else    
    echo "file does not exist"
fi
;;
esac

Answer 1

如果你有 sudo 权限，你可以使用 pgrep 获取进程 ID。见man pgrep

....  
a)
echo " parent pid is $PPID"

#you can get child id from parent process id.
pid=$(sudo pgrep --parent $PPID)
##now you have process id as pid

echo " pid is $pid"

b)...

*我没有足够的声誉来评论和回答sudo

Answer 2

您始终可以使用 $$ 来获取 PID。

a)
echo " parent pid is $PPID"
echo " pid is $$"
;;

我相信这就是你想要做的。