Python 程序不工作，并且 Python IDLE 不会突出显示错误

Question

所以我喜欢编程，喜欢十六进制；我正在使用 python 中的计算器将十六进制转换为十进制，以十进制执行所需的操作，然后将答案转换为十六进制。该程序不工作，标准的python IDLE（安装python时标准的那个）说有一个语法错误，但不是像正常的错误一样高亮，它只是说“无效的语法”当我按下“F5”键（运行程序），然后打开外壳。我在 shell 中逐行输入程序，并在 def ansDef(oper): 函数内的某个地方。 代码如下：

print("Valid operations: +, -, *, /, ^, rt")
numA = input("Enter first number: ")
oper = input("Enter operation: ")
numB = input("Enter second number: ")
baseA = int(numA, 16)
baseB = int(numB, 16)
numBRT = float(1) / float(baseNumB)
def ansDef(oper):
    return{
        "+":
            baseAns == float(baseA) + float(baseB)
        "-":
            baseAns == float(baseA) - float(baseB)
        "*":
            baseAns == float(baseA) * float(baseB)
        "/":
            baseAns == float(baseA) / float(baseB)
        "^":
            baseAns == float(baseA) ** float(baseB)
        "rt":
            baseAns == float(baseA) ** float(numBRT)
    }.get(oper, return{
            print("ERROR: INVALID OPERATION")
        })
ans = hex(baseAns)
print(ans)

Answer 1

只需重写你的代码作为Python语法的例子，真的值得阅读Python3或Python2官方教程一次。

print("Valid operations: +, -, *, /, ^, rt")
numA = input("Enter first number: ")
oper = input("Enter operation: ")
numB = input("Enter second number: ")
baseA = int(numA, 16)
baseB = int(numB, 16)

def ansDef(oper, a, b):
    if oper == "+":
        return a + b
    elif oper == "-":
        return a - b
    elif oper == "*":
        return a * b
    elif oper == "/":
        return a / b
    elif oper == "^":
        return a ** b
    elif oper == "rt":
        return a ** 1.0 / b
    else:
        raise Exception("ERROR: INVALID OPERATION")

try:
    baseAns = ansDef(oper, float(baseA), float(baseB))
    ans = hex(int(baseAns))
    print(ans)
except Exception as e:
    print(e)