【发布时间】:2020-09-18 01:22:29
【问题描述】:
我有 2 个 JSON 文件:
Json1 文件:
[
{
"json1language": "English"
},
{
"json1language": "French"
},
{
"json1language": "Spanish"
}
]
Json2 文件:
[
{
"json2country": "Canada",
"json2languages": [
{
"json2language": "English"
},
{
"json2language": "French"
}
]
},
{
"json2country": "Mexico",
"json2languages": [
{
"json2language": "English"
},
{
"json2language": "Spanish"
}
]
},
{
"json2country": "France",
"json2languages": [
{
"json2language": "French"
}
]
}
]
我希望当我点击json1language => showDialog 时显示json2country 和json2language 匹配条件json2language == json1language
示例:单击“英语”=> 显示 json2country:“加拿大”; json2language: "英语","法语" & json2country: "墨西哥"; json2language: "English","Spanish" (因为 json2language 包含 "English")
所以请帮帮我,这是主文件
import 'package:flutter/material.dart';
import 'dart:convert';
List<Json1> json1FromJson(String str) => List<Json1>.from(json.decode(str).map((x) => Json1.fromJson(x)));
String json1ToJson(List<Json1> data) => json.encode(List<dynamic>.from(data.map((x) => x.toJson())));
class Json1 {
Json1({
this.json1Language,
});
String json1Language;
factory Json1.fromJson(Map<String, dynamic> json) => Json1(
json1Language: json["json1language"],
);
Map<String, dynamic> toJson() => {
"json1language": json1Language,
};
}
List<Json2> json2FromJson(String str) => List<Json2>.from(json.decode(str).map((x) => Json2.fromJson(x)));
String json2ToJson(List<Json2> data) => json.encode(List<dynamic>.from(data.map((x) => x.toJson())));
class Json2 {
Json2({
this.json2Country,
this.json2Languages,
});
String json2Country;
List<Json2Language> json2Languages;
factory Json2.fromJson(Map<String, dynamic> json) => Json2(
json2Country: json["json2country"],
json2Languages: List<Json2Language>.from(json["json2languages"].map((x) => Json2Language.fromJson(x))),
);
Map<String, dynamic> toJson() => {
"json2country": json2Country,
"json2languages": List<dynamic>.from(json2Languages.map((x) => x.toJson())),
};
}
class Json2Language {
Json2Language({
this.json2Language,
});
String json2Language;
factory Json2Language.fromJson(Map<String, dynamic> json) => Json2Language(
json2Language: json["json2language"],
);
Map<String, dynamic> toJson() => {
"json2language": json2Language,
};
}
class Json1Services {
static Future<List<Json1>> getData() {
String jsonString = '''
[
{
"json1language": "English"
},
{
"json1language": "French"
},
{
"json1language": "Spanish"
}
]
''';
return Future.value(json1FromJson(jsonString));
}
}
class Json2Services {
static Future<List<Json2>> getData() {
String jsonString = '''
[
{
"json2country": "Canada",
"json2languages": [
{
"json2language": "English"
},
{
"json2language": "French"
}
]
},
{
"json2country": "Mexico",
"json2languages": [
{
"json2language": "English"
},
{
"json2language": "Spanish"
}
]
},
{
"json2country": "France",
"json2languages": [
{
"json2language": "French"
}
]
}
]
''';
return Future.value(json2FromJson(jsonString));
}
}
class Json extends StatefulWidget {
@override
_JsonState createState() => _JsonState();
}
class _JsonState extends State<Json> {
List<Json1> _json1 = [];
List<Json2> _json2 = [];
@override
void initState() {
super.initState();
setState(() {
Json1Services.getData().then((data) {
setState(() {
_json1 = data;
});
});
Json2Services.getData().then((data) {
setState(() {
_json2 = data;
});
});
});
}
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(),
body: SingleChildScrollView(
child: Row(
mainAxisAlignment: MainAxisAlignment.spaceEvenly,
children: [
for (Json1 j1 in _json1)
RaisedButton(
child: Text(j1.json1Language),
onPressed: () => showDialog(
context: context,
builder: (_) {
return AlertDialog(
content: null,
);
}))
],
),
));
}
}
【问题讨论】:
-
您只需要一个
Map<String, Set<Json2>>- 这里String键是一个语言名称,您的工作是从现有数据中填充它 -
@pskink 你能给我完整的代码吗?我真的是一个编码新手