【问题标题】:Transport error with socket io套接字 io 传输错误
【发布时间】:2018-09-17 23:49:57
【问题描述】:

我试图在与套接字 io 断开连接时向后端发送用户名,当我在取消订阅套接字连接时将用户名作为参数传递时,它给了我问题传输错误。

这是我的代码

客户端“连接”只是一个变量:

      messages = [];
      connectedUsers = [];
      connection;
      message;
      Username = JSON.parse(localStorage.getItem('user')).username;
      users = [];

ngOnDestroy() {
    this.connection.unsubscribe({username: 'emons'});
}

服务器端这是我处理发射的地方,控制台日志正常,但 'console.log(usersConnected[i] +' was spliced')' 不起作用,因为条件从未满足:

const app = express();

const port = 3000;
const server = http.Server(app);
const io = socketIo(server);

var usersConnected = [];

    io.on('connection', function(socket){
        console.log('a user connected');
        /*socket.on('new-connection', function(user) {
            io.sockets.emit('newUser', {type: 'new-connection', username: user});
        }); */


        socket.on('disconnect', function(user){
            console.log(user + '   jsjasdjbskjcbawsjbsajdbasjabdsj')
            for (var i = 0; i < usersConnected.length; i++) {
                if (user.username == usersConnected[i]) {
                    usersConnected.splice(i, 1);
                    console.log(usersConnected[i] +' was spliced')
                };
            } 
            console.log(usersConnected);
            console.log('user disconnected');
        });


        socket.on('add-message', function(msg){
            console.log('added message');
            io.sockets.emit('message', {type: 'new-message', username: msg.user, text: msg.message});
        });
        //trying to get all the users.
        socket.on('chat-connection', (data) => {
            socket.join(data.username);
            console.log(data.username);
            usersConnected.push(data.username);
            io.emit('new-user', usersConnected);
        })


    });

chat.service.ts:

   sendMessage(message) {
      this.socket.emit('add-message', message);
    }

    sendUser(user) {
      console.log(user);//print correctly
      this.socket.emit('chat-connection', user);
    }

    removeUser(user) {
      this.socket.emit('remove-user', user);
    }

    getMessages() {
      let observable = new Observable(observer => {
        this.socket = socketIo(this.url);
        this.socket.on('message', (data) => {
          observer.next(data);
        });

        return () => {
          this.socket.disconnect();
        }
      });
      return observable;
    }

  getUsers() {
    let userObservable = new Observable(observer => {
      this.socket = socketIo(this.url);
      this.socket.on('new-user', (data) => {
        observer.next(data);
      });
    });
    return userObservable;
  }

【问题讨论】:

  • 只是好奇,你是在查看控制台日志吗?
  • 我得到了控制台日志,除了 'usersConnected[i]...' 一个,因为条件从未满足,因为用户 = 打印时出现传输错误
  • 你的this.connection.unsubscribe功能是什么?

标签: javascript angular socket.io


【解决方案1】:

我认为你的服务器端可以是:

let allClients = [];

socket.on('connection', function(client) {
    allClients.push(client);

    client.once('disconnect', function() {
        console.log('Got disconnect!');

        client.disconnect();
        var i = allClients.indexOf(client);
        allClients.splice(i, 1);
    });

    client.on('LEAVE_ROOM', function (data) {
        console.log('Got disconnect!', data);

        client.disconnect();
        var i = allClients.indexOf(client);
        allClients.splice(i, 1);
    });
});

disconnect 网络断开事件。您可以在初始化 SocketIO Server 时设置超时:

pingTimeout(Number): 没有pong包多少毫秒认为连接关闭(60000)

客户端可以是:

$(window).on('beforeunload', function(){
    socket.emit('LEAVE_ROOM', reason);
});

【讨论】:

  • 我曾尝试实现这一点,但不幸的是,我没有成功。无论如何,您是否可以以我使用的形式实现代码,即使用已传递的套接字我为上下文添加了额外的代码。我正处于最后期限,因此收到了不寻常的请求。
  • @Samlemonts 你试过从客户那里发送socket.emit('LEAVE_ROOM', reason);吗?
猜你喜欢
  • 2022-01-05
  • 1970-01-01
  • 2017-06-23
  • 2017-01-24
  • 2016-06-28
  • 1970-01-01
  • 1970-01-01
  • 1970-01-01
  • 2014-11-03
相关资源
最近更新 更多