无法快速比较/返回零对象

Question

我不是 Objective-C 的新手，但我是 swift 的新手。如果它们在 Objective-C 中为零，我曾经比较对象，但我无法迅速做到这一点。

func getCurrentUser() -> Users{

    let fetchRequest = NSFetchRequest(entityName: "Users")
    var fetchedUsers = NSArray()
    do {
        let fetchedEntities = try self.managedObjectContext.executeFetchRequest(fetchRequest) as NSArray
        fetchedUsers = fetchedEntities
    } catch {
        // Do something in response to error condition
    }

    var userToSend = Users()

    for user in fetchedUsers{

        let currentUser = user as! Users
        if(currentUser.isSignedIn == 1)
        {
            userToSend = currentUser
            break
        }
    }
    return userToSend
}

如果我的 userToSend 为 nil，我无法检查调用该方法的位置，代码崩溃。

这是我的代码崩溃的地方：

    let currentUser = UserDBService().getCurrentUser()

    let userID = String(currentUser.userId)

我该怎么做？

更新

我使用了迈克尔的答案，但仍然崩溃：

使用了 Eendje 的解决方案，我明白了：

Answer 1

func getCurrentUser() -> Users? {
    let fetchRequest = NSFetchRequest(entityName: "Users")
    let fetchedUsers = (try? managedobjectContext.executeFetchRequest(fetchRequest)) as? [Users] ?? []

    // If there are no instances of Users with isSignedIn == 1, it returns nil
    guard let index = fetchedUsers.indexOf({ $0.isSignedIn == 1 }) else { return nil }

    // Since it passed the guard, it can return the user
    return fetchedUsers[index]
}

// Returns an optional String
let userID = String(getCurrentUser()?.userID)

稍微改写一下你的函数，应该可以工作了。

Answer 2

详细说明我的评论，看起来getCurrentUser 应该返回一个可选：

func getCurrentUser() -> Users? {

    let fetchRequest = NSFetchRequest(entityName: "Users")
    var fetchedUsers = NSArray()
    do {
        let fetchedEntities = try self.managedObjectContext.executeFetchRequest(fetchRequest) as NSArray
        fetchedUsers = fetchedEntities
    } catch {
        // Do something in response to error condition
    }

    for user in fetchedUsers {
        if let currentUser = user as? Users {
            if(currentUser.isSignedIn == 1) {
                return currentUser
            }
        }
    }
    return nil
}

那么你可以这样称呼它：

if let currentUser = UserDBService().getCurrentUser() {
    let userID = String(currentUser.userId)
} else {
    // no current user
}

Answer 3

您可以通过任何方式修复此崩溃

if let currentUser = UserDBService().getCurrentUser() {
    let userID = String(currentUser.userId)
} else {

}

或

 let currentUser = UserDBService().getCurrentUser()
     if(currentUser!=nil){
        let userID = String(currentUser.userId)
     }else{
        // Nil handling code
     }

Answer 4

    func getCurrentUser() -> Users? {
        let fetchRequest = NSFetchRequest(entityName: "Users")
        let fetchedUsers = (try? managedobjectContext.executeFetchRequest(fetchRequest)) as? [Users] ?? []

     returns nil
        guard let index = fetchedUsers.indexOf({ $0.isSignedIn == 1 }) 
        else 
        { 
            return nil 
        }

        return fetchedUsers[index]
    }

//Call your method like this
let userID = String(getCurrentUser(context)?.userID)

如果您正在使用共享上下文或者您正在使用 self.context，请删除 context，然后在此处使用 self.context。