Django REST Framework generics.RetrieveUpdateDestroyAPIView 返回所有记录而不是一个答案

【问题标题】：Django REST Framework generics.RetrieveUpdateDestroyAPIView return all records instead of oneDjango REST Framework generics.RetrieveUpdateDestroyAPIView 返回所有记录而不是一个
【发布时间】：2018-06-28 06:32:32
【问题描述】：

我是 DRF 的新手，正在尝试构建一个 rest API，我已将模型、URL、视图和序列化程序设置为：

模型.py：

services = (
    ('Single', 'Single'),
    ('Multiple', 'Multiple'),
)


class DeploymentOnUserModel(models.Model):
    deployment_name = models.CharField(max_length=256, )
    credentials = models.TextField(blank=False)
    project_name = models.CharField(max_length=150, blank=False)
    project_id = models.CharField(max_length=150, blank=True)
    cluster_name = models.CharField(max_length=256, blank=False)
    zone_region = models.CharField(max_length=150, blank=False)
    services = models.CharField(max_length=150, choices=services)
    configuration = models.TextField()
    routing = models.TextField()

    def save(self, **kwargs):
        if not self.id and self.services == 'Multiple' and not self.routing and not self.configuration:
            raise ValidationError("You must have to provide routing for multiple services deployment.")
        super().save(**kwargs)

来自 urls.py：

from django.urls import path, include
# from .routers import router
from . import apiview

app_name = 'deployments'

urlpatterns = [
    # path('', include(router.urls), name='deployments'),
    path('deployments/', apiview.DeploymentsList.as_view(), name='deployment-list'),
    path('deployments/<int:pk>/', apiview.DeploymentDetail.as_view(), name='deployment_detail')

]

来自 apiview.py：

class DeploymentDetail(generics.RetrieveUpdateDestroyAPIView):

    def retrieve(self, request, *args, **kwargs):
        pk = self.kwargs.get('pk')

        return Response(DeploymentOnUserModel.objects.get(pk=kwargs['pk']))

来自 serializers.py：

class DeploymentOnUserSerializer(serializers.ModelSerializer):
    class Meta:
        model = DeploymentOnUserModel
        fields = '__all__'

当我尝试访问时：http://127.0.0.1:8000/api/v1/deployments/?pk=1/ 它应该返回 id=1 的单个对象，但它会返回所有对象。

【问题讨论】：

标签： python django python-3.x django-rest-framework drf-nested-routers

【解决方案1】：

与其将 pk 作为 GET 参数传递，不如将其作为 url 的一部分传递，如下所示：

http://127.0.0.1:8000/api/v1/deployments/1/

您尝试使用由DeploymentsList 执行的http://127.0.0.1:8000/api/v1/deployments/?pk=1/ 的URL，因为它不包含pk url kwarg。

您还应该在将对象作为响应返回之前对其进行序列化：

class DeploymentDetail(generics.RetrieveUpdateDestroyAPIView):

    def retrieve(self, request, *args, **kwargs):
        pk = self.kwargs.get('pk')
        object = DeploymentOnUserModel.objects.get(pk=kwargs['pk'])
        serializer = DeploymentOnUserSerializer(object)
        return Response(serializer.data)

【讨论】：

嗨@neverwalkaloner，它返回page not found error
@AbdulRehman 尝试在 urlpattern 中添加斜杠：'deployments/<int:pk>/'。
它仍然返回所有对象！
嗨@neverwalkaloner，我已经添加了urls.py 文件。
当我尝试 get 方法而不是 retrieve 时，url 错误已经消失，但它返回另一个错误：Object of type 'DeploymentOnUserModel' is not JSON serializable

【解决方案2】：

当我尝试 get 方法而不是检索 url 错误时，但它返回另一个错误：“DeploymentOnUserModel”类型的对象是不可 JSON 序列化

我知道现在很晚，但在你的 apiview.py 中

class DeploymentDetail(generics.RetrieveUpdateDestroyAPIView):
    serializer_class = DeploymentOnUserSerializer()   

    
   def get_queryset(self):
      pk = self.request.GET.get("pk")
      return deployment = DeploymentOnUserModel.objects.get(pk=pk)

【讨论】：