【发布时间】:2013-03-01 11:46:11
【问题描述】:
我在 Yii 中搜索时遇到问题。我有两个模型:Teams 和 Workers。在网站上有一个名为“Team Workers”的页面,我想在其中显示 CGridView 小部件,其中搜索显示来自团队的工人(团队 ID 作为 _GET 参数传递)。
我在TeamsController:
public function actionWorkers($id)
{
$model = Teams::model()->findByPk($id);
$workers = Workers::model();
$workers->unsetAttributes();
if(isset($_GET['Workers']))
{
$_GET['Workers']['idTeam'] = $id;
$workers->attributes = $_GET['Workers'];
}
else {
$workers->attributes = array('idTeam' => $id);
}
$teamWorkers = $workers;
$this->render('workers', array(
'model' => $model,
'teamWorkers' => $teamWorkers
));
}
在视图文件中:
<?php $this->widget('zii.widgets.grid.CGridView', array(
'id'=>'team-workers-grid',
'dataProvider'=>$teamWorkers->search(),
'filter' => $teamWorkers,
'columns'=>array(
'name',
'surname',
array(
'id' => 'idWorker',
'class' => 'CCheckBoxColumn',
'checked' => '$data->confirmer',
'selectableRows' => '2',
// 'headerTemplate' => '{item}'
)
),
)); ?>
我得到了错误:
CDbCommand nie zdołał wykonać instrukcji SQL: SQLSTATE[23000]: Integrity constraint
violation: 1052 Column 'idTeam' in where clause is ambiguous. The SQL statement
executed was: SELECT COUNT(DISTINCT `t`.`idWorker`) FROM `workers` `t` LEFT OUTER JOIN
`teams` `Team` ON (`t`.`idTeam`=`Team`.`idTeam`) WHERE ((idTeam=:ycp0) AND (Team.name
LIKE :ycp1))
当我不设置 idTeam 属性时 - 它工作正常。这很奇怪 - 在常规 CRUD admin 页面上 - idTeam 属性被传递并且工作正常。
怎么办?
【问题讨论】:
-
请把代码贴在你要加入的地方。很可能是搜索方法。