in_array 函数不起作用

Question

我有一个 XML 文件，我将它读入 PHP 数组，以便使用 CakePHP 的 XML::toArray($xmlString) 函数进行处理。

一切正常，我可以轻松地处理数据，但是，当我尝试运行 in_array 检查时，它一直返回 false，即使我知道值在那里。

这是 if 语句：

$xmlArray = Xml::toArray($xmlString);
$menus = $xmlArray['navigation'];
$groupId = array($groupId); // Group ID of logged in user, in my case 1
$loggedInId = array($loggedInId); // User ID, in my case 182
//I change them both into arrays, as the second param needs to be an array, and in the XML file, there could only be one value, in which case it's "translated" as a string
//$submenu == foreach($menu['submenu']['menu'] as $subenu)
if(in_array($submenu['permission']['group'],$groupId) || in_array($submenu['permission']['user'],$loggedInId)) {
    //do stuff
}

这是 XML 文件（导航位）：

<?xml version="1.0" encoding="utf-8"?>
<navigation>
    <menu>
        <title>Home</title>
        <url>home</url>
        <submenus>
            <menu>
                <title>In memory of...</title>
                <url>memoriams</url>
                <image>memoriam</image>
                <permission>
                    <group>1</group>
                    <user>0</user>
                </permission>
            </menu>
            <menu>
                <title>Reports</title>
                <url>reports</url>
                <image>report</image>
                <permission>
                    <group>4</group>
                    <group>5</group>
                    <user>252</user>
                    <user>182</user>
                    <user>234</user>
                </permission>
            </menu>
        </submenus>
    </menu>
</navigation>

菜单仅在第一种情况下显示。也就是说，如果组/用户只有 1 个值。如果它有多个值，它只是不显示子菜单。

这里是数组的调试：

array(
    'menu' => array(
        'title' => 'Home',
        'url' => 'home',
        'submenus' => array(
            'menu' => array(
                (int) 0 => array(
                    'title' => 'In memory of...',
                    'url' => 'memoriams',
                    'image' => 'memoriam',
                    'permission' => array(
                        'group' => '1',
                        'user' => '0'
                    )
                ),
                (int) 1 => array(
                    'title' => 'Reports',
                    'url' => 'reports',
                    'image' => 'report',
                    'permission' => array(
                        'group' => array(
                            (int) 0 => '4',
                            (int) 1 => '5'
                        ),
                        'user' => array(
                            (int) 0 => '252',
                            (int) 1 => '182',
                            (int) 2 => '234'
                        )
                    )
                )
            )
        )
    )
)

有人知道为什么它不想工作吗？

Answer 1

函数in_array的第一个参数是needle，第二个参数是array来搜索匹配！！

参考：PHP Manual

Answer 2

foreach ($menu['menu']['submenus']['menu'] as $submenu) {
  $group = $submenu['permission']['group'];
  $user = $submenu['permission']['user'];
  if(in_array($group, (array) $groupId) || in_array($user, (array) $loggedInId)) {
    //do stuff
  }
}