如何使这个火柴人具有互动性？答案

【问题标题】：How Can This Stickman Be Made to Be Interactive?如何使这个火柴人具有互动性？
【发布时间】：2017-11-30 17:47:49
【问题描述】：

所以，我需要通过用户输入让火柴人移动。当用户点击某个部分（头、手、脚和后部）时，他应该移动，但不知道该怎么做。如果可能的话，还需要在角色周围设置一个限制，可能是矩形，以便限制每个部分可以拉动多远。我的代码见下文；

// Created by Charlie Carr - (28/11/17 - /11/17)
    import java.awt.*;
    import java.applet.Applet;
    import javax.swing.*;
    import java.awt.Graphics;
    import java.awt.geom.*;
    import java.awt.image.BufferedImage;
    //Imports complete

    //Suppress warning about undeclared static final serialVersionUID field in VS Code
    @SuppressWarnings("serial")
    public class Animator extends JPanel {
            public static class AnimatorWindow extends JPanel {
                    public void paint(Graphics page) {
                            setBackground(Color.gray);
                            setForeground(Color.white);
                            super.paintComponent(page);
                            page.drawString("Stickmen Animation Station", 150, 15);
                            //draw the head
                            //x1, y1, x2, y2
                            page.drawOval(90, 60, 20, 20);
                            // draw the body
                            page.drawLine(100, 80, 100, 110);
                            // draw the hands
                            page.drawLine(100, 90, 80, 105);
                            page.drawLine(100, 90, 120, 105);
                            //draw the legs, he hasn't a leg to stand on..
                            page.drawLine(100, 110, 85, 135);
                            page.drawLine(100, 110, 115, 135);
                    }
            }

            public static void main(String[] args) {
                    AnimatorWindow displayPanel = new AnimatorWindow();

                    JPanel content = new JPanel();
                    content.setLayout(new BorderLayout());
                    content.add(displayPanel, BorderLayout.CENTER);
                    //declare window size
                    int x = 480;
                    int y = 240;

                    JFrame window = new JFrame("GUI");
                    window.setContentPane(content);
                    window.setSize(x, y);
                    window.setLocation(101, 101);
                    window.setVisible(true);

            }

    }

【问题讨论】：

标签： java swing graphics jpanel

【解决方案1】：

使用MouseListener处理鼠标事件。

另外，您应该重写paintComponent() 方法而不是paint()，因为paint() 也会绘制边框和其他内容。

public static class AnimatorWindow extends JPanel implements MouseListener{
    public AnimatorWindow(){
        setBackground(Color.gray);
        setForeground(Color.white);
        //add the listener
        addMouseListener(this);
    }
    public void paintComponent(Graphics page) {
        super.paintComponent(page);
        //You should not alter the Graphics object passed in
        Graphics2D g = (Graphics2D) page.create();

        //draw your stuff with g
        g.drawString("Stickmen Animation Station", 150, 15);
        .......

        //finish
        g.dispose();
    }


    public void mouseEntered(MouseEvent e){}
    public void mouseExited(MouseEvent e){}
    public void mousePressed(MouseEvent e){}
    public void mouseReleased(MouseEvent e){}
    public void mouseClicked(MouseEvent e){
        //implement your clicking here
        //Use e.getX() and e.getY() to get the click position
    }
}

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编辑：您的问题还包括动画，您可以使用javax.swing.Timer 来做到这一点。

【讨论】：