Python当它们都在体内时如何对值进行排序？答案

【问题标题】：Python How to sort values when they are all in body?Python当它们都在体内时如何对值进行排序？
【发布时间】：2020-10-31 10:04:55
【问题描述】：

import requests
import time
from bs4 import BeautifulSoup


start_time = time.time()
url = 'https://secure.runescape.com/m=hiscore_oldschool/index_lite.ws?player=zezima'
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36'}

resp = requests.get(url, headers=headers)
print("Server: " + resp.headers['server'])
print(resp.text)
print("Job done in" + " %f seconds" % (time.time() - start_time))

我正在尝试学习如何对不同的值（它们的统计数据）进行排序并执行例如总等级：1465
统计数据总是以相同的顺序排列，如果没有找到，则为 -1。我希望它只输出第二个值的总水平。在这种情况下，1465。理想的输出应该是这样的：

总等级：1465

示例响应：

690953,1465,27957906
711820,76,1343681
658073,76,1342072
1033645,75,1271864
1091165,75,1252551

【问题讨论】：

标签： python extract

【解决方案1】：

这是一个简单的换行符分割，然后用逗号分割第一行的例子。

lines = resp.text.split('\n')
first_line = lines[0].split(',')
print('Total level: ' + first_line[1] )

如果不总是有结果，您可以添加一些错误检查。

【讨论】：

【解决方案2】：

 import requests 
 import bs4 
 import time

 url  = 'https://books.toscrape.com/catalogue/page-1.html' # this link will be usefull 
 its made for webscraping , and all price is fake 
 # you can practies on this website ...
 start  = time.time()

 req = requests.get(url)
 soup = bs4.BeautifulSoup(req.text,'lxml') # using BeautifulSoup for sorting html 
 #script

 end = time.time()
 print("Job done in" + " %f seconds" % (end - start))

#if you want something in the website if it was class use (.) before the stuf  if we 
want product price of first page of books
product_price = soup.select('.price_color')

for i in product_price:
print('price = ' +i.getText())

【讨论】：