【问题标题】:Query on contact list for select contacts - Multiple URI Android?查询选择联系人的联系人列表 - 多个 URI Android?
【发布时间】:2018-08-07 02:51:07
【问题描述】:

如何在一个查询中设置ContactsContract.CommonDataKinds.EmailContactsContract.CommonDataKinds.Phone 的查询并获取ID、姓名、电话号码和电子邮件...?

如下代码:

private void getContactList() {
        String id = "";
        String name = "";
        String phoneNo = "";
        String mail = "";
        ContentResolver cr = getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
                null, null, null, null);
        if ((cur != null ? cur.getCount() : 0) > 0) {
            while (cur != null && cur.moveToNext()) {
                id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
                name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));

                //if (cur.getInt(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)) > 0) {
                Cursor pCur = cr.query(
                        ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
                        null,
                        ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
                        new String[]{id}, null);

                Cursor eCur = cr.query(
                        ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                        null,
                        ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?",
                        new String[]{id}, null);

                if (pCur != null) {
                    while (pCur.moveToNext()) {
                        phoneNo = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                        if (phoneNo != null && !TextUtils.isEmpty(phoneNo)) {
                            //Log.i("ASDASDASDASDD", "id: " + id);
                            Log.i("ASDASDASDASDD", "Name: " + name);
                            Log.i("ASDASDASDASDD", "Phone Number: " + phoneNo);
                            Log.i("ASDASDASDASDD", "email: ");
                        } else {
                            phoneNo = "";
                        }
                    }
                    pCur.close();
                } else {
                    phoneNo = "";
                }
                if (eCur != null) {
                    while (eCur.moveToNext()) {
                        mail = eCur.getString(eCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
                        if (mail != null && !TextUtils.isEmpty(mail)) {
                            //Log.i("ASDASDASDASDD", "id: " + id);
                            Log.i("ASDASDASDASDD", "Name: " + name);
                            Log.i("ASDASDASDASDD", "Phone Number: " + phoneNo);
                            Log.i("ASDASDASDASDD", "email: " + mail);
                        } else {
                            mail = "";
                        }
                    }
                    eCur.close();
                } else {
                    mail = "";
                }
            }
            //}
        }
        if (cur != null) {
            cur.close();
        }
    }

我需要同时拥有电话、姓名、身份证、电子邮件和...。

【问题讨论】:

    标签: android android-sqlite android-contacts android-cursor contactscontract


    【解决方案1】:

    EmailPhone 表实际上是 Data 表的便利 uri,其中包含所有类型的所有数据(电子邮件、电话等!)

    String[] projection = new String[] { Data.CONTACT_ID, Data.DISPLAY_NAME, Data.MIMETYPE, Data.DATA1 };
    Cursor cur = getContentResolver().query(Data.CONTENT_URI, projection, Data.MIMETYPE + " IN ('" + Email.CONTENT_ITEM_TYPE + "' , '" + Phone.CONTENT_ITEM_TYPE +"')", null, null);
    
    while ((cur != null) && cur.moveToNext()) {
        long contactId = cur.getLong(0);
        String name = cur.getString(1);
        String type = cur.getString(2);
        String data = cur.getString(3);
    
        if (type == Email.CONTENT_ITEM_TYPE) {
           Log.e("Data", "Found an email: " + contactId + ", " + name + ", " + type + ", " + data);
        } else {
           Log.e("Data", "Found a phone: " + contactId + ", " + name + ", " + type + ", " + data);
        }
    }
    

    【讨论】:

      【解决方案2】:

      解决了我的问题:

          private void XXXXX() {
          StringBuilder phoneNo = new StringBuilder();
          StringBuilder email = new StringBuilder();
          ContentResolver cr = getContentResolver();
          Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
                  null, null, null, null);
          if ((cur != null ? cur.getCount() : 0) > 0) {
              while (cur != null && cur.moveToNext()) {
                  String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
                  String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
      
                  Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
                          ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = " + id, null,
                          null);
                  if (phones != null) {
                      while (phones.moveToNext()) {
                          phoneNo.append("\n").append(phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)));
      
                      }
                      phones.close();
                  } else {
                      phoneNo = new StringBuilder();
                  }
      
      
                  Cursor emailC = getContentResolver().query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,
                          ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = " + id, null,
                          null);
                  if (emailC != null) {
                      while (emailC.moveToNext()) {
                          email.append("\n").append(emailC.getString(emailC.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA)));
                      }
                      emailC.close();
                  } else {
                      email = new StringBuilder();
                  }
      
      
                  Log.e("ASDASASDAS",
                          "name : " + name
                                  + " \n " +
                                  " phone : " + phoneNo
                                  + " \n " +
                                  " email : " + email
                                  + " \n");
                  phoneNo = new StringBuilder();
                  email = new StringBuilder();
      
              }
          }
      }
      

      【讨论】:

      • 哦不!请不要这样做...您可以通过一个查询来完成,我会尽快发布答案
      • @marmor。我正在使用我的解决方案,我的代码是它的基础,但您的解决方案很好,我接受您的回复。 ;)
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