【发布时间】:2019-10-14 19:07:57
【问题描述】:
我正在编写一段代码用于学习目的,我想比较使用不同算法对列表进行排序所需的时间。我尝试使用装饰器,但由于 mergeSort 函数是递归的,它给了我每次递归的结果。如果可能的话,我想找到一种方法来总结结果。由于我对装饰师很陌生,我不确定在这种情况下可以做什么。有没有办法使用装饰器来实现这个目标?
import random
import functools
import time
def timeIt(func):
@functools.wraps(func)
def newfunc(*args, **kwargs):
startTime = time.time()
func(*args, **kwargs)
elapsedTime = time.time() - startTime
print('function [{}] finished in {} ms'.format(
func.__name__, int(elapsedTime * 1000)))
return newfunc
@timeIt
def mergeSort(L):
if len(L) > 1:
mid = len(L) // 2
left = L[:mid]
right = L[mid:]
mergeSort(left)
mergeSort(right)
i = j = k = 0
while i < len(left) and j < len(right):
if left[i] < right[j]:
L[k] = left[i]
i += 1
else:
L[k] = right[j]
j += 1
k += 1
while i < len(left):
L[k] = left[i]
i += 1
k += 1
while j < len(right):
L[k] = right[j]
j += 1
k += 1
@timeIt
def selectionSort(L):
for fillslot in range(len(L) - 1, 0, -1):
maxpos = 0
for location in range(1, fillslot + 1):
if L[location] > L[maxpos]:
maxpos = location
temp = L[fillslot]
L[fillslot] = L[maxpos]
L[maxpos] = temp
randomList = random.sample(range(10000), 10000)
mergeSort(randomList.copy())
selectionSort(randomList.copy())
输出:
[...] truncated
function [mergeSort] finished in 7 ms
function [mergeSort] finished in 15 ms
function [mergeSort] finished in 33 ms
function [mergeSort] finished in 68 ms
function [selectionSort] finished in 2049 ms
【问题讨论】:
-
您可以编写一个专用于调用 mergeSort 的函数,例如
mergeSortObserver并用您的装饰器装饰它。由于这个特殊函数只会被调用一次,你会得到想要的行为。
标签: python function recursion time decorator