【发布时间】:2011-08-10 18:27:22
【问题描述】:
现在,我可以检索电话号码并将我的 editText 的文本设置为该号码。但是,当我尝试获取姓氏或名字时,它不起作用。请注意我注释掉的内容。
这是我的代码:
import android.app.Activity;
import android.content.Intent;
import android.database.Cursor;
import android.net.Uri;
import android.os.Bundle;
import android.provider.ContactsContract;
import android.provider.ContactsContract.CommonDataKinds.Phone;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
public class main extends Activity {
private static final int CONTACT_PICKER_RESULT = 1001;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button getContacts = (Button)findViewById(R.id.getContacts);
getContacts.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent i = new Intent(Intent.ACTION_PICK,
ContactsContract.CommonDataKinds.Phone.CONTENT_URI);
startActivityForResult(i, CONTACT_PICKER_RESULT);
}
});
}
protected void onActivityResult(int reqCode, int resultCode, Intent data) {
super.onActivityResult(reqCode, resultCode, data);
if(resultCode == RESULT_OK) {
switch (reqCode) {
case CONTACT_PICKER_RESULT:
Cursor cursor = null;
String number = "";
String lastName ="";
try {
Uri result = data.getData();
//get the id from the uri
String id = result.getLastPathSegment();
//query
cursor = getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone._ID + " = ? " , new String[] {id}, null);
// cursor = getContentResolver().query(Phone.CONTENT_URI,
// null, Phone.CONTACT_ID + "=?", new String[] { id },
// null);
int numberIdx = cursor.getColumnIndex(Phone.DATA);
if(cursor.moveToFirst()) {
number = cursor.getString(numberIdx);
//lastName = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME));
} else {
//WE FAILED
}
} catch (Exception e) {
//failed
} finally {
if (cursor!=null) {
cursor.close();
}
EditText numberEditText = (EditText)findViewById(R.id.number);
numberEditText.setText(number);
//EditText lastNameEditText = (EditText)findViewById(R.id.last_name);
//lastNameEditText.setText(lastName);
}
}
}
【问题讨论】:
-
有什么问题?究竟是什么不起作用?
-
对于任何想要分别使用名字和姓氏的人,请参阅:stackoverflow.com/questions/4301064/…Krzysztof 的回答对我特别有用。
标签: android