【发布时间】:2023-03-13 03:15:01
【问题描述】:
我有一个看起来像这样的 XML(缩短)
<TrainingCenterDatabase>
<Activities>
<Activity Sport="Running">
<Id>2014-04-28T23:54:41.000Z</Id>
<Lap StartTime="2014-04-28T23:54:41.000Z">
<TotalTimeSeconds>284.957</TotalTimeSeconds>
<DistanceMeters>1000.0</DistanceMeters>
<MaximumSpeed>4.160999774932861</MaximumSpeed>
<Calories>67</Calories>
<AverageHeartRateBpm>
<Value>152</Value>
</AverageHeartRateBpm>
<MaximumHeartRateBpm>
<Value>162</Value>
</MaximumHeartRateBpm>
<Intensity>Active</Intensity>
<TriggerMethod>Manual</TriggerMethod>
</Lap>
<Lap>
SAME STUFF HERE
</Lap>
</Activity>
<Activities>
</TrainingCenterDatabase>
我是这样提取信息的:
XmlNodeList lapList = doc.GetElementsByTagName("Lap");
activity = new Activity();
foreach (XmlNode lap in lapList)
{
var split = new Lap
{
StartTime = DateTime.Parse(lap.Attributes[0].Value),
LapDistance = ConvertToDouble(lap.ChildNodes.Item(1).InnerXml),
LapMaximunSpeed = ConvertToDouble(lap.ChildNodes.Item(2).InnerXml),
LapCalories = ConvertToInt(lap.ChildNodes.Item(3).InnerXml),
LapAverageHeartRate = ConvertToInt(lap.ChildNodes.Item(4).InnerText),
LapMaximumHeartRate = ConvertToInt(lap.ChildNodes.Item(5).InnerText),
};
我的问题是,有没有办法减少这种错误?喜欢(引用元素名称?):
LapDistance = ConvertToDouble(lap.ChildNodes.Item["DistanceMeters"].InnerXml),
这种情况的最佳做法是什么?
【问题讨论】:
-
有什么理由不使用 XmlSerialization 或 LINQ to XML?
标签: c# xml serialization xml-parsing