如何在 Spinner 中选择项目以将其用作字符串？

Question

只是想看看我是否可以找出我如何在微调器中选择项目并将其存储在一个字符串中，我已经看到其他关于此的帖子，人们说将这一行放入代码中： （在我下面发布的代码的最后一行下面）

String Genders = Gender.getSelectedItem().toString();

我尝试了，但它在下面给了我一条红线 (getselecteditem()) - 说微调器不包含 getselecteditem() 的定义

这是我的代码：

  Spinner Gender;
  protected override void OnCreate(Bundle savedInstanceState)
    {
        base.OnCreate(savedInstanceState);
        SetContentView(Resource.Layout.Form);

        var Genders = new String[]
        {
            "Male", "Female"
        };
        BaseMale = 2000;
        Gender = FindViewById<Spinner>(Resource.Id.spinner1);
        Gender.Adapter = new ArrayAdapter<string>(this, Android.Resource.Layout.SimpleSpinnerDropDownItem, Genders);

非常感谢您的帮助！ :)

Answer 1

您可能需要实现选择句柄 (ItemSelected)，就像在 https://developer.xamarin.com/guides/android/user_interface/spinner/ 的这个示例中一样：

protected override void OnCreate (Bundle bundle)
{
        base.OnCreate (bundle);

        // Set our view from the "Main" layout resource
        SetContentView (Resource.Layout.Main);

        Spinner spinner = FindViewById<Spinner> (Resource.Id.spinner);

        spinner.ItemSelected += new EventHandler<AdapterView.ItemSelectedEventArgs> (spinner_ItemSelected);
        var adapter = ArrayAdapter.CreateFromResource (
                this, Resource.Array.planets_array, Android.Resource.Layout.SimpleSpinnerItem);

        adapter.SetDropDownViewResource (Android.Resource.Layout.SimpleSpinnerDropDownItem);
        spinner.Adapter = adapter;
}

这里是句柄，所选项目的索引在这里显示为e.Position。

private void spinner_ItemSelected (object sender, AdapterView.ItemSelectedEventArgs e)
{
        Spinner spinner = (Spinner)sender;

        string toast = string.Format ("The planet is {0}", spinner.GetItemAtPosition (e.Position));
        Toast.MakeText (this, toast, ToastLength.Long).Show ();
}