【发布时间】:2016-10-05 11:44:51
【问题描述】:
Form1 有一个带有按钮的文本框,该按钮会调出 Form2,它是具有 DataGridView 的 Form3 的筛选器屏幕。当我双击 DataGridView Row 时,我需要它将一个值传递给 Form1 上的 TextBox(它将保持打开和活动状态)当我双击该行时,我可以获得正确的值以显示在 MessageBox 中,但我不能似乎传递了 Form1 的值。
表格1
private void btnDepartmentSearch_Click(object sender, EventArgs e)
Employee_Department_Search_Filters EDSF = new Employee_Department_Search_Filters();
EDSF.Owner = this;
EDSF.Show();
Form2
private void search()
{
Employee_Department_Search_Results EDSR = new Employee_Department_Search_Results();
EDSR.Owner = this.Owner;
string departmentContains = tbDepartment.Text;
adapt = new SqlDataAdapter("select uid_department, str_code AS [Department Code], str_name AS [Department Name] from tbl_department where str_name like '%" + departmentContains + "%'", conString);
ds = new System.Data.DataSet();
adapt.Fill(ds, "Department");
EDSR.dgvDepartmentSearch.DataSource = ds.Tables[0];
EDSR.dgvDepartmentSearch.Columns[0].AutoSizeMode = DataGridViewAutoSizeColumnMode.Fill;
EDSR.dgvDepartmentSearch.Columns[1].AutoSizeMode = DataGridViewAutoSizeColumnMode.Fill;
EDSR.dgvDepartmentSearch.Columns[2].AutoSizeMode = DataGridViewAutoSizeColumnMode.Fill;
EDSR.dgvDepartmentSearch.Columns[0].Visible = false;
this.Close();
EDSR.ShowDialog(this.Owner);
}
表格 3
public void rowClick()
{
Employee_Maintenance EM = new Employee_Maintenance();
SqlConnection conn = new SqlConnection(myconnection);
conn.Open();
SqlCommand comm = new SqlCommand("select str_code from tbl_department where uid_department = " + dgvDepartmentSearch.SelectedCells[0].Value, conn);
SqlDataReader read = null;
read = comm.ExecuteReader();
while(read.Read())
{
departmentCode = read["str_code"].ToString();
}
EM.txtDepartment.Text = departmentCode;
conn.Close();
this.Close();
}
【问题讨论】:
-
不是答案,但您应该处理掉您的 SqlCommand 和 SqlDataReader 对象,并使用参数来避免 SQL 注入。
-
如果你想看到它,你必须添加 EM.Show()。考虑引发一个事件,以便表单可以自行更新文本框。
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我不想再次打开表单,因为表单已经处于活动状态
标签: c#