从子类函数调用超级函数[重复]

Question

我希望在覆盖超类函数的子类函数中调用超类函数。例如：

var a = function(x) {
    this.val = x || 0;
};
a.prototype.print = function() {
    console.log("Class A");
};

var b = function(x, y) {
   this.y = y || 0;
   a.call(this, x);
};
b.prototype = Object.create(a.prototype);
b.prototype.constructor = b;
b.prototype.print = function() {
    console.log("b inherits from ");
    // call to superclass print function (a.print) 
};

当子类已经覆盖了超类函数时，如何从子类调用超类打印函数？

Answer 1

您可以使用superclass.prototype.method.call(argThis, parameters)。在您的情况下，没有参数将是 a.prototype.print.call(this);

所以，你的代码是

var a = function(x) {
    this.val = x || 0;
};
a.prototype.print = function() {
    console.log("Class A");
};

var b = function(x, y) {
   this.y = y || 0;
   a.call(this, x);
};
b.prototype = Object.create(a.prototype);
b.prototype.constructor = b;
b.prototype.print = function() {
    console.log("b inherits from ");
    a.prototype.print.call(this);

};