【发布时间】:2015-02-19 19:16:28
【问题描述】:
在我的 Android 应用程序中,我有一个包含用户联系人列表的姓名和电话号码的类。我还有一个列出联系人姓名的微调器。当用户从微调器中选择姓名时,我想Log 联系人的姓名和号码。
这里是MainActivity.java
package com.example.mycompy.myapp;
import android.content.ContentResolver;
import android.database.Cursor;
import android.support.v7.app.ActionBarActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.AdapterView;
import android.widget.ArrayAdapter;
import android.widget.Spinner;
import android.provider.ContactsContract;
import java.util.ArrayList;
public class MainActivity extends ActionBarActivity implements AdapterView.OnItemSelectedListener {
// this class will hold contact names and numbers
public class ContactInfo {
public String contactName, phoneNumber;
public ContactInfo(String contactName, String phoneNumber){
this.contactName = contactName;
this.phoneNumber = phoneNumber;
}
@Override
public String toString(){
return contactName;
}
}
public Spinner contactSpinner;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ArrayList<ContactInfo> contactList = new ArrayList<ContactInfo>();
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,null,null,null,null); // A SQL query for contacts data table, in Java form, I think...
contactSpinner = (Spinner) findViewById(R.id.contact_list);
contactSpinner.setOnItemSelectedListener(this);
// If there are contacts, this code goes
if(cur.getCount()>0){
while(cur.moveToNext()){
String id = cur.getString(
cur.getColumnIndex(ContactsContract.Contacts._ID)
);
String name = cur.getString(
cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)
);
if(
Integer.parseInt(
cur.getString(
cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)
)
) > 0
){
Cursor pCur = cr.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[]{id},null
);
while(pCur.moveToNext()){
String phone = pCur.getString(
pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)
);
// Add contact's info to `contactList`
ContactInfo newContact = new ContactInfo(name,phone);
contactList.add(newContact);
Log.v("onCreate", String.valueOf(newContact));
}
pCur.close();
}
}
}
// Add items to spinner
ArrayAdapter adapter = new ArrayAdapter(this,android.R.layout.simple_spinner_dropdown_item,contactList);
contactSpinner.setAdapter(adapter); // Spinner shows contact names only, which is what I want spinner to show
}
@Override
public void onItemSelected(AdapterView<?> parent, View view, int pos, long id) {
parent.getItemAtPosition(pos);
Log.v("onItemSelected", String.valueOf(parent.getItemAtPosition(pos))); // When user selects a contact, this Logs just the contact name, but I want contact name AND number
}
@Override
public void onNothingSelected(AdapterView<?> parent) {
// Another interface callback
}
// Rest of code...
}
如何编辑onItemSelected() 以便Logs 选择联系人姓名和电话号码?
【问题讨论】:
-
当问题只是关于从您的 ContactInfo 类记录信息时,您不需要显示所有这些 Android 代码。
标签: java android class object spinner