Listview 点击打开小listview

Question

我有一个项目，它是一个教育集。当项目开始打开起始页面并且您单击列表视图中显示的任何课程时。您单击了打开该课程的课程。但我看起来我有 +400 课程的主题。像这样， 生物学; 动物，秀丽隐杆线虫：模式生物，黑腹果蝇，无脊椎动物单孔目 我有这样的 +40 课。我想如果我点击 listview 上的课程。它可以在同一个班级中打开一个新的 listview。像多个 listview 吗？打开一个小列表视图。这将是点击课程的主题。 我该怎么做请帮忙:)

    private ListView lv1;
     private String lv_arr[]={"Lessons,Leson1,Leson2,etc..."}; 
        @Override
        public void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);        
            setContentView(R.layout.konu);

            lv1=(ListView)findViewById(R.id.listView1);
            AdView adView = (AdView) this.findViewById(R.id.adView);
            AdRequest adRequest = new AdRequest.Builder().build();
            adView.loadAd(adRequest);

            lv1=(ListView)findViewById(R.id.listView1);

            // By using setAdpater method in listview we an add string array in list.

            lv1.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1 , lv_arr));     
            lv1.setOnItemClickListener(new OnItemClickListener() {
                public void onItemClick(AdapterView<?> parent, View view,
                    int position, long id) {

        if(position == 0)
        {

                 Intent myIntent = new Intent(soru.this, mat1.class);
                     startActivityForResult(myIntent, 0);
        }

        if(position == 1)
        {

                 Intent myIntent =  new Intent(soru.this, mat2.class);
                     startActivityForResult(myIntent, 0);
        }
        if(position == 2)
        {

                 Intent myIntent =  new Intent(soru.this, geo.class);
                     startActivityForResult(myIntent, 0);
        }
        if(position == 3)
        {

                 Intent myIntent =  new Intent(soru.this, fizik.class);
          startActivityForResult(myIntent, 0);
        }
                     if(position == 4)
                    {

                   Intent myIntent =  new Intent(soru.this, kimya.class);
            startActivityForResult(myIntent, 0);
                    }
                     if(position == 5)
                        {

                       Intent myIntent =  new Intent(soru.this, biyoloji.class);
                startActivityForResult(myIntent, 0);
                        }
                     if(position == 6)
                        {

                       Intent myIntent =  new Intent(soru.this, edebiyat.class);
                startActivityForResult(myIntent, 0);
                        }
                     if(position == 7)
                        {

                       Intent myIntent =  new Intent(soru.this, espanol.class);
                startActivityForResult(myIntent, 0);
                        }    

            }
          });
        }

}

Answer 1

我认为最适合您的解决方案是使用ExpandableListView。 here 给出了一个非常简单的使用教程，教你如何实现。