基于输入，如何将列表的元素分类为类的对象？答案

【问题标题】：Based on an input, how can I classify elements of a list into objects for classes?基于输入，如何将列表的元素分类为类的对象？
【发布时间】：2021-03-03 01:48:08
【问题描述】：

我有代码：

class tune:
    def __init__(self, title, artist, duration):
        self.title = title
        self.artist = artist
        self.duration = duration
class play:

    def __init__(self):
        self.tracks = []

    def add(self, song):
    self.tracks.append[song]
    
    def look(self,song):
    print (self.artist,"-",self.title)

n=input() #number of input
song=play()
for i in range(n):
    x = input().split(',')
    song.title=x[1]
    song.artist=x[0]
    song.duration=x[2]
song.look()

对于每个输入，我必须将其设为属于其类的对象并将其添加到列表中。当调用 song.look 时，它应该打印出列表中的标题和艺术家。例如，如果输入是：

2
Artic Monkeys,R U Mine?,324
Artic Monkeys,Do I wanna know?,253

程序执行时应该输出：

Artic Monkeys - R U Mine?
Artic Monkeys - Do I wanna know?

我不知道我是否分别将输入附加到它的对象，我做错了什么吗？

【问题讨论】：

标签： python-3.x list class

【解决方案1】：

您没有提供太多关于问题所在的上下文，但查看您的代码有点明显。试试这个：

class Tune:

    def __init__(self, title, artist, duration):
        self.title = title
        self.artist = artist
        self.duration = duration

class Play:

    def __init__(self):
        self.tracks = []

    def add(self, song):
        self.tracks.append(song)
    
    def look(self, song):
        for song in self.tracks:
            print(f"{song.artist} - {song.title}")

n = int(input("Enter the number of tracks to add"))
playlist = Play()

for i in range(n):
    title, artist, duration = input("Enter the title, artist, and duration of a track").split(',')
    song = Tune(title, artist, duration)
    playlist.add(song)

playlist.look()

【讨论】：