【问题标题】:How To Make A Timer That Counts Time at a Factor of Real Time in Python?如何在 Python 中制作一个以实时因子计算时间的计时器?
【发布时间】:2017-09-13 02:56:23
【问题描述】:

此代码会在您的屏幕上弹出一个小秒表。
我做了一些复制粘贴以获得第二个计数器。
我试图让第二个计数器的计数时间比计数器的实际时间慢。
就像顶部计数器每经过 1 分钟一样,第二个计数器经过 15 秒。
我试过把 * 0.25 放在任何地方,但没有得到它。

from Tkinter import *
import time

class StopWatch(Frame):  
    """ Implements a stop watch frame widget. """                                                                
    def __init__(self, parent=None, **kw):        
        Frame.__init__(self, parent, kw)
        self._start = 0.0        
        self._elapsedtime = 0.0
        self._running = 0
        self.timestr = StringVar()               
        self.makeWidgets()
        self.makeWidgets2()

    def makeWidgets(self):                         
        """ Make the time label. """
        l = Label(self, textvariable=self.timestr)
        self._setTime(self._elapsedtime)
        l.pack(fill=X, expand=NO, pady=2, padx=2)                      

    def makeWidgets2(self):                         
        """ Make the time label. """
        l = Label(self, textvariable=self.timestr)
        self._setTime(self._elapsedtime)
        l.pack(fill=X, expand=NO, pady=2, padx=2)    

    def _update(self): 
        """ Update the label with elapsed time. """
        self._elapsedtime = time.time() - self._start
        self._setTime(self._elapsedtime)
        self._elapsedtime = (self._elapsedtime * 0.1)
        self._timer = self.after(50, self._update)


    def _setTime(self, elap):
        """ Set the time string to Minutes:Seconds:Hundreths """
        minutes = int(elap/60)
        seconds = int(elap - minutes*60.0)
        hseconds = int((elap - minutes*60.0 - seconds)*100)                
        self.timestr.set('%02d:%02d:%02d' % (minutes, seconds, hseconds))

    def Start(self):                                                     
        """ Start the stopwatch, ignore if running. """
        if not self._running:
            ''' make self.start the time now - zero'''
            self._start = time.time() - self._elapsedtime
            self._update()
            self._running = 1

    def Stop(self):                                    
        """ Stop the stopwatch, ignore if stopped. """
        if self._running:
            self.after_cancel(self._timer)            
            self._elapsedtime = time.time() - self._start    
            self._setTime(self._elapsedtime)
            self._running = 0

    def Reset(self):                                  
        """ Reset the stopwatch. """
        self._start = time.time()         
        self._elapsedtime = 0.0    
        self._setTime(self._elapsedtime)


def main():
    root = Tk()
    sw = StopWatch(root)
    sw.pack(side=TOP)

    Button(root, text='Start', command=sw.Start).pack(side=LEFT)
    Button(root, text='Stop', command=sw.Stop).pack(side=LEFT)
    Button(root, text='Reset', command=sw.Reset).pack(side=LEFT)
    Button(root, text='Quit', command=root.quit).pack(side=LEFT)

    root.mainloop()

if __name__ == '__main__':
    main()

【问题讨论】:

  • 将秒数除以 4 应该可以解决您的问题。

标签: python time


【解决方案1】:

您需要两个必须分开的时间字符串并分别更新它们。例如,在您的 __init__ 函数中,您可以定义:

self.timestr = StringVar()
self.timestr2 = StringVar()

然后你可以在 Start 中单独更新它们,并传递一个速率参数来调整时间:

self._update(self.timestr, 1.0)
self._update(self.timestr2, 0.5)  

这是一个完整的工作示例:

from Tkinter import *
import time

class StopWatch(Frame):
    """ Implements a stop watch frame widget. """
    def __init__(self, parent=None, **kw):
        Frame.__init__(self, parent, kw)
        self._start = 0.0
        self._elapsedtime = 0.0
        self._running = 0
        self.timestr = StringVar()
        self.timestr2 = StringVar()
        self.makeWidgets()
        self.makeWidgets2()

    def makeWidgets(self):
        """ Make the time label. """
        l = Label(self, textvariable=self.timestr)
        self._setTime(self._elapsedtime, self.timestr)
        l.pack(fill=X, expand=NO, pady=2, padx=2)

    def makeWidgets2(self):
        """ Make the time label. """
        l = Label(self, textvariable=self.timestr2)
        self._setTime(self._elapsedtime, self.timestr2)
        l.pack(fill=X, expand=NO, pady=2, padx=2)

    def _update(self, string_obj, rate):
        """ Update the label with elapsed time. """
        self._elapsedtime = time.time() - self._start
        self._setTime(self._elapsedtime*rate, string_obj)
        self._timer = self.after(50, self._update, string_obj, rate)


    def _setTime(self, elap, string_obj):
        """ Set the time string to Minutes:Seconds:Hundreths """
        minutes = int(elap/60)
        seconds = int(elap - minutes*60.0)
        hseconds = int((elap - minutes*60.0 - seconds)*100)
        string_obj.set('%02d:%02d:%02d' % (minutes, seconds, hseconds))

    def Start(self):
        """ Start the stopwatch, ignore if running. """
        if not self._running:
            ''' make self.start the time now - zero'''
            self._start = time.time() - self._elapsedtime
            self._update(self.timestr, 1.0)
            self._update(self.timestr2, 0.5)
            self._running = 1

    def Stop(self):
        """ Stop the stopwatch, ignore if stopped. """
        if self._running:
            self.after_cancel(self._timer)
            self._elapsedtime = time.time() - self._start
            self._setTime(self._elapsedtime)
            self._running = 0

    def Reset(self):
        """ Reset the stopwatch. """
        self._start = time.time()
        self._elapsedtime = 0.0
        self._setTime(self._elapsedtime)


def main():
    root = Tk()
    sw = StopWatch(root)
    sw.pack(side=TOP)

    Button(root, text='Start', command=sw.Start).pack(side=LEFT)
    Button(root, text='Stop', command=sw.Stop).pack(side=LEFT)
    Button(root, text='Reset', command=sw.Reset).pack(side=LEFT)
    Button(root, text='Quit', command=root.quit).pack(side=LEFT)

    root.mainloop()

if __name__ == '__main__':
    main()

【讨论】:

  • 谢谢。尽管停止和重置按钮不适用于此新功能。停止后也无法重新启动。如果你不喜欢,我会自己解决。最好的答案。
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