在 Python 中创建一个每 x 次调用一个函数的 for 循环

Question

我有这些数据：

granularity: 1h
start_time: 2021-4-28T1:1:1.342380Z
end_time: 2021-4-29T1:1:1.342360Z

我想创建一个类似这样的伪代码：

for start_time to end_time:
    call function on each interval of granularity

在给定的示例中，我将从 start_time 到 end_time 每 1 小时调用一次函数。时间和粒度参数可以更改，并且不固定为我的示例中给出的值。可以是 60 分 5 秒...

经过一番思考并在博客和 Stack Overflow 上进行搜索后，我不知道该怎么做。我可以尝试什么？

Answer 1

我使用 datetime 库编写了这个，这是大多数 Python 安装的标准配置。它需要以秒为单位的时间，因此，60 秒为一分钟，3600 秒为一小时。

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代码：

from datetime import datetime

def alert(time):
    hourtime = time / 60
    print(f"It's Been {time} seconds or {hourtime} Hours")


def timer(seconds, start_time, end_time):
    curr_time = datetime.now()
    formatted_time = curr_time.strftime('%S')
    lasttime = formatted_time
    localtimer = 0 
    while True:
        curr_time = datetime.now()

        formatted_time = curr_time.strftime('%S')
        time_ =  curr_time.strftime('%H%M')


        if int(time_) <= int(end_time) - 1: # Check to see if the current time is less than the end time
            if int(time_) >= int(start_time): # check to see if it's Greater or equal to the start time
                if int(lasttime) != int(formatted_time): # if so it does the alert function every x seconds
                    lasttime = formatted_time
                    print(localtimer) # You can Keep or remove this line it's just for counting how many seconds have gone by.
                    localtimer += 1
                if localtimer == int(seconds):
                    alert(seconds)
                    localtimer = 0
        

timer(seconds=5, start_time=1547, end_time=1548) # It takes time in seconds, start and end time are both in the 24 hr format just without the ":" so instead of 15:44, it would be 1544

（注意：OP 纠正了我它需要一个开始和结束时间，所以我添加了它）。

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这是没有开始和结束时间的旧代码：

from datetime import datetime

def alert(time):
    hourtime = time / 60
    print(f"It's Been {time} seconds or {hourtime} Hours")


def timer(seconds):
    curr_time = datetime.now()
    formatted_time = curr_time.strftime('%S')
    lasttime = formatted_time
    localtimer = 0 
    while True:
        curr_time = datetime.now()
        formatted_time = curr_time.strftime('%S')
        if int(lasttime) != int(formatted_time):
            lasttime = formatted_time
            print(localtimer) # You can Keep or remove this line it's just for counting how many seconds have gone by.
            localtimer += 1
        if localtimer == int(seconds):
            alert(seconds)
            localtimer = 0


timer(5) # It takes time in seconds so 3600 will be 3600 seconds which is an hour and 5 is 5 seconds, so a minute would be 60 and so on and so forth