从特定日期的半小时列表中排除特定半小时

Question

我正在使用预约系统，并且有一个表格可以收集用户的开始日期和结束日期以检查顾问的可用性，假设您选择开始日期为 3 月 27 日，结束日期为 3 月 29 日，是三天，然后我显示三行，每行包含办公室的营业时间，间隔半小时预定会议，这就是它的样子。

出现的时间应该会隐藏已经预订的时间段。

我能够完美地显示每天的可用时间，除非会议已被预订为 3 月 28 日的时间 02:00PM - 02-30PM，那么这个时间将被隐藏所有天，除了只有3 月 28 日。

以下是我为此目的使用的代码

    <?php

$start    = new DateTime('09:00:00');
$end      = new DateTime('16:00:01'); // add 1 second because last one is not included in the loop
$interval = new DateInterval('PT30M');
$period   = new DatePeriod($start, $interval, $end);

$existing_time = array(
    array(
        'start_time' => '2014-03-28T14:00:00+1100',
        'end_time' => '2014-03-28T14:30:00+1100'
    ),
    array(
        'start_time' => '2014-03-28T15:00:00+1100',
        'end_time' => '2014-03-28T15:30:00+1100'
    )
);

?>

    <div id="accordion2" class="accordion">
        <?php for ($i = 0; $i < 3; $i++) {
            ?>
            <div class="accordion-group">
                <div class="accordion-heading">
                    <a href="#collapse<?php echo $i ?>" data-parent="#accordion2" data-toggle="collapse"
                       class="accordion-toggle collapsed">
                        <?php echo date('Y-m-d', strtotime('2014-03-27' . ' + ' . $i . ' day')) ?>
                    </a>
                </div>
                <div class="accordion-body collapse" id="collapse<?php echo $i ?>" style="height: 0px;">
                    <div class="accordion-inner">

                        <?php
                        $booked = array();
                        foreach ($existing_time as $ex) {
                            $dt = new DateTime($ex['start_time']);
                            $booked[] = $dt->format('h:ia');
                        }

                        $previous = '';
                        foreach ($period as $dt) {
                            $current = $dt->format("h:ia");
                            if (!empty($previous) && !in_array($previous, $booked)) {
                                echo "<input name='time' type='radio' value='{$previous}|{$current}'> {$previous}-{$current}<br/>";
                            }
                            $previous = $current;
                        }
                        ?>
                    </div>
                </div>
            </div>
        <?php } ?>
    </div>

我将非常感谢任何帮助。

Answer 1

<?php
$start    = new DateTime('09:00:00');
$interval = new DateInterval('PT30M');

$existing_time = array(
    array(
        'start_time' => '2014-03-21T14:00:00+1100',
        'end_time' => '2014-03-21T14:30:00+1100'
    ),
    array(
        'start_time' => '2014-03-20T15:00:00+1100',
        'end_time' => '2014-03-20T15:30:00+1100'
    )
);

$booked = array();
foreach ($existing_time as $ex) {
    $dt = new DateTime($ex['start_time']);
    $booked[] = $dt->format('Y-m-d h:ia');
}

for ($i = 0; $i < 3; $i++) {
    if (0 !== $i) {
        $start->modify("+1 day");
        $start->setTime(9, 0);
    }
    $end = clone $start;
    $end = $end->setTime(16, 1); // add 1 second because last one is not included in the loop

    $previous = null;
    $period   = new DatePeriod($start, $interval, $end);
    foreach ($period as $dt) {
        $current  = $dt->format("h:ia");
        if (!empty($previous)) {
            $pr_short = $previous->format("h:ia");
            $pr_long  = $previous->format("Y-m-d h:ia");
            if (!in_array($pr_long, $booked)) {
                echo "<input name='time' type='radio' value='{$pr_short}|{$current}'> {$pr_short}-{$current}<br/>";
            }
        }
        $previous = $dt;
    }
}

See it in action